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Six identical cards are placed on a table. Each card has number 1 marked on one side and number 2marked on its other side. All the six cards are placed such that the number 1 is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many tries, can the cards be turned upside down such that all the six cards show number 2 on the upper side?
  • a)
    3
  • b)
    5
  • c)
    7
  • d)
    This cannot be achieved
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Six identical cards are placed on a table. Each card has number 1marke...
In 1st trial, 1st 4 cards are turned,
In 2nd trial, 2nd, 3rd, 4th and 5th cards are turned.
In 3rd trial, 2nd, 3rd, 4th and 6th cards are turned.
After each trial, number shown on upside is can be seen through this table-
Clearly, After three trial, number on upside face of each card =2
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Community Answer
Six identical cards are placed on a table. Each card has number 1marke...
Understanding the Problem:
To achieve all six cards showing number 2 on the upper side, we need to flip the cards which currently show number 1. We are allowed to flip exactly four cards in one try.

Strategy:
Since we need to flip all six cards to show number 2 on the upper side, we need to come up with a systematic approach to achieve this. Here's how we can do it:

First Try:
- Flip any four cards. This leaves us with two cards showing number 1 and four cards showing number 2.

Second Try:
- Now, flip the two cards showing number 1. This will make all six cards show number 2 on the upper side.
Therefore, the cards can be turned upside down such that all six cards show number 2 on the upper side in 3 tries (4 cards in the first try and 2 cards in the second try).
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Six identical cards are placed on a table. Each card has number 1marked on one side and number 2marked on its other side. All the six cards are placed such that the number 1 is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many tries, can the cards be turned upside down such that all the six cards show number 2on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer?
Question Description
Six identical cards are placed on a table. Each card has number 1marked on one side and number 2marked on its other side. All the six cards are placed such that the number 1 is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many tries, can the cards be turned upside down such that all the six cards show number 2on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Six identical cards are placed on a table. Each card has number 1marked on one side and number 2marked on its other side. All the six cards are placed such that the number 1 is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many tries, can the cards be turned upside down such that all the six cards show number 2on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Six identical cards are placed on a table. Each card has number 1marked on one side and number 2marked on its other side. All the six cards are placed such that the number 1 is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many tries, can the cards be turned upside down such that all the six cards show number 2on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer?.
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