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A body starts from rest travels a distance x in first two seconds and a distance y in next two seconds. The relation between x and y is
- a)y = 4x
- b)y = x
- c)y = 3x
- d)y = 2x
Correct answer is option 'C'. Can you explain this answer?
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A body starts from rest travels a distance x in first two seconds and ...
Solution:
Let the acceleration of the body be 'a'.
Using the first equation of motion, we have:
x = (1/2)at²
y = (1/2)a(t+2)² - (1/2)at²
y = (1/2)a(t² + 4t + 4) - (1/2)at²
y = (1/2)a(4t + 4)
y = 2a(t + 1)
Dividing y by x, we get:
y/x = 2(t+1) / t
y/x = 2 + 2/t
Since we know that the time taken for the first distance (x) is 2 seconds and the time taken for the second distance (y) is 4 seconds (2+2), we can substitute 't' with 2 in the above equation.
y/x = 2 + 2/2
y/x = 3
Therefore, the relation between x and y is y = 3x.
Hence, option 'C' is the correct answer.
Let the acceleration of the body be 'a'.
Using the first equation of motion, we have:
x = (1/2)at²
y = (1/2)a(t+2)² - (1/2)at²
y = (1/2)a(t² + 4t + 4) - (1/2)at²
y = (1/2)a(4t + 4)
y = 2a(t + 1)
Dividing y by x, we get:
y/x = 2(t+1) / t
y/x = 2 + 2/t
Since we know that the time taken for the first distance (x) is 2 seconds and the time taken for the second distance (y) is 4 seconds (2+2), we can substitute 't' with 2 in the above equation.
y/x = 2 + 2/2
y/x = 3
Therefore, the relation between x and y is y = 3x.
Hence, option 'C' is the correct answer.
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A body starts from rest travels a distance x in first two seconds and a distance y in next two seconds. The relation between x and y isa)y = 4xb)y = xc)y = 3xd)y = 2xCorrect answer is option 'C'. Can you explain this answer?
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