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If a =cos2α + isin2α, b = cos2β + isin2β, c = cos2γ+isin2γ and d = cos2δ + isin2δ, then
  • a)
    √2 cos (α + β + γ + δ)
  • b)
    2cos (α + β + γ + δ)
  • c)
    cos (α + β + γ + δ)
  • d)
    none of these.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If a =cos2α + isin2α, b = cos2β + isin2β, c = co...
We have,
a = cos2α + isin2α  ...(1)
b = cos2β + isin2β  ...(2)
c = cos2γ + isin2γ  ...(3)
d = cos2δ + isin2δ  ...(4)
Now,
abcd=(cos 2α + isin 2α)(cos 2β + isin 2β)(cos 2γ + isin 2γ)(cos 2δ + isin 2δ)
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If a =cos2α + isin2α, b = cos2β + isin2β, c = cos2γ+isin2γ and d = cos2δ + isin2δ, thena)√2 cos (α + β + γ + δ)b)2cos (α + β + γ + δ)c)cos (α + β + γ + δ)d)none of these.Correct answer is option 'B'. Can you explain this answer?
Question Description
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