The average of 10 numbers is 20. If a number equal in value to the lar...
Given Information:
- There are 10 numbers.
- The average of these 10 numbers is 20.
Adding the largest number:
- Let's assume the largest number in the given set is 'x'.
- If we add 'x' to the given set, the total sum of the numbers would increase by 'x'.
- The new sum of the 11 numbers would be the sum of the original 10 numbers plus 'x'.
- The new average would be the new sum divided by 11.
- It is given that the new average is 1 more than the original average, which means the new average is 21.
- So, we have the equation: (sum of the original 10 numbers + x) / 11 = 21.
Finding the value of 'x':
- We know that the average of the original 10 numbers is 20, so the sum of the original 10 numbers is 20 multiplied by 10, which is 200.
- Substituting this value in the equation, we have: (200 + x) / 11 = 21.
- Solving this equation, we get: 200 + x = 231.
- Therefore, x = 231 - 200 = 31.
Deleting the largest number:
- If we delete the largest number from the given set, the total sum of the remaining 9 numbers would decrease by 31.
- The new sum would be the sum of the original 10 numbers minus 31.
- The new average would be the new sum divided by 9.
- So, the new average would be (200 - 31) / 9 = 169 / 9 = 18.77.
Conclusion:
- Therefore, if instead of adding the largest number, we delete it, the new average would be 18.77.
- Hence, the correct answer is option 'B' - 18.77.