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For an 8-pole induction motor supplied with power by a 6 pole Alternator at 1200 revolutions per minute, the value of motor speed at slip of 3% is –
  • a)
    800 RPM
  • b)
    400 RPM
  • c)
    873 RPM
  • d)
    900 RPM
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
For an 8-pole induction motor supplied with power by a 6 pole Alternat...
Given
Speed of Alternator, N = 1200 RPM
Number of Alternator poles, P = 6
Supply frequency, f = PN/120 = 60 Hz
Hence, for number of 8 poles in Induction motor, the synchronous speed or speed of rotating field is: Ns = 120f/P = 900 RPM
Let Nis actual speed of motor.
Thus, Percentage Slip, S % = ((Ns – Nr)/Ns) x 100
Substituting the values, we get: Nr = Ns (1-S/100) = 873 RPM.
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Community Answer
For an 8-pole induction motor supplied with power by a 6 pole Alternat...
To find the motor speed at a slip of 3%, we can use the formula:

Motor speed = Alternator speed * (1 - Slip)

The alternator speed is given as 1200 revolutions per minute.

Slip is the difference between the synchronous speed and the actual motor speed, divided by the synchronous speed. The synchronous speed can be calculated using the formula:

Synchronous speed = (120 * Frequency) / Number of poles

The frequency of the power supply is not given, so we will assume it is 60 Hz (standard frequency in many countries). The number of poles is given as 6 for the alternator, and 8 for the motor.

Using these values, we can calculate the synchronous speed:

Synchronous speed = (120 * 60) / 6 = 1200 revolutions per minute

Now we can calculate the motor speed at a slip of 3%:

Motor speed = 1200 * (1 - 0.03) = 1200 * 0.97 = 1164 revolutions per minute
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