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For a balanced three phase, three wire system with input power of 10kW, at 0.9 power factor, the readings on both wattmeter are _______ respectively.
- a)7kW, 3kW
- b)6350W, 3650W
- c)5000W, 5000W
- d)7600W, 1200W
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
For a balanced three phase, three wire system with input power of 10kW...
Let reading of one Wattmeter = W1
Reading of second Wattmeter = W2
Input Power, P = W1+W2 = √3VLILcosφ = 10000 ________1
Power Factor, cosφ = 0.9
Phase angle, φ = 25.8 degrees
Therefore, W1 = VLILcos(30-φ) = 0.99VLIL = 6350W
W2 = VLILcos(30+φ) = 0.56VLIL = 3650W
Reading of second Wattmeter = W2
Input Power, P = W1+W2 = √3VLILcosφ = 10000 ________1
Power Factor, cosφ = 0.9
Phase angle, φ = 25.8 degrees
Therefore, W1 = VLILcos(30-φ) = 0.99VLIL = 6350W
W2 = VLILcos(30+φ) = 0.56VLIL = 3650W
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Community Answer
For a balanced three phase, three wire system with input power of 10kW...
Given information:
- Three-phase, three-wire system
- Input power = 10 kW
- Power factor = 0.9
To find:
The readings on both wattmeters
Solution:
In a balanced three-phase system, the power is evenly distributed among the three phases. Each phase carries one-third of the total power.
Step 1:
Calculate the total power in the system using the formula:
Total power = √3 x Line voltage x Line current x Power factor
Step 2:
Since the power is evenly distributed among the three phases, each phase carries one-third of the total power.
Power per phase = Total power / 3
Step 3:
The readings on the wattmeters can be calculated as follows:
Wattmeter 1 reading = Total power - Power per phase
Wattmeter 2 reading = Power per phase
Calculations:
Given:
Input power = 10 kW
Power factor = 0.9
Step 1:
Total power = √3 x Line voltage x Line current x Power factor
We are not given the line voltage or line current, so we cannot calculate the total power.
Step 2:
Power per phase = Total power / 3
Since we don't know the total power, we cannot calculate the power per phase.
Step 3:
Wattmeter 1 reading = Total power - Power per phase
Wattmeter 2 reading = Power per phase
Since we cannot calculate the total power or power per phase, we cannot determine the readings on the wattmeters.
Therefore, the answer cannot be determined based on the given information.
- Three-phase, three-wire system
- Input power = 10 kW
- Power factor = 0.9
To find:
The readings on both wattmeters
Solution:
In a balanced three-phase system, the power is evenly distributed among the three phases. Each phase carries one-third of the total power.
Step 1:
Calculate the total power in the system using the formula:
Total power = √3 x Line voltage x Line current x Power factor
Step 2:
Since the power is evenly distributed among the three phases, each phase carries one-third of the total power.
Power per phase = Total power / 3
Step 3:
The readings on the wattmeters can be calculated as follows:
Wattmeter 1 reading = Total power - Power per phase
Wattmeter 2 reading = Power per phase
Calculations:
Given:
Input power = 10 kW
Power factor = 0.9
Step 1:
Total power = √3 x Line voltage x Line current x Power factor
We are not given the line voltage or line current, so we cannot calculate the total power.
Step 2:
Power per phase = Total power / 3
Since we don't know the total power, we cannot calculate the power per phase.
Step 3:
Wattmeter 1 reading = Total power - Power per phase
Wattmeter 2 reading = Power per phase
Since we cannot calculate the total power or power per phase, we cannot determine the readings on the wattmeters.
Therefore, the answer cannot be determined based on the given information.
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For a balanced three phase, three wire system with input power of 10kW, at 0.9 power factor, the readings on both wattmeter are _______ respectively.a)7kW, 3kWb)6350W, 3650Wc)5000W, 5000Wd)7600W, 1200WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about For a balanced three phase, three wire system with input power of 10kW, at 0.9 power factor, the readings on both wattmeter are _______ respectively.a)7kW, 3kWb)6350W, 3650Wc)5000W, 5000Wd)7600W, 1200WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a balanced three phase, three wire system with input power of 10kW, at 0.9 power factor, the readings on both wattmeter are _______ respectively.a)7kW, 3kWb)6350W, 3650Wc)5000W, 5000Wd)7600W, 1200WCorrect answer is option 'B'. Can you explain this answer?.
For a balanced three phase, three wire system with input power of 10kW, at 0.9 power factor, the readings on both wattmeter are _______ respectively.a)7kW, 3kWb)6350W, 3650Wc)5000W, 5000Wd)7600W, 1200WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about For a balanced three phase, three wire system with input power of 10kW, at 0.9 power factor, the readings on both wattmeter are _______ respectively.a)7kW, 3kWb)6350W, 3650Wc)5000W, 5000Wd)7600W, 1200WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a balanced three phase, three wire system with input power of 10kW, at 0.9 power factor, the readings on both wattmeter are _______ respectively.a)7kW, 3kWb)6350W, 3650Wc)5000W, 5000Wd)7600W, 1200WCorrect answer is option 'B'. Can you explain this answer?.
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