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Calculate the number of electrons in 4 gram of helium?
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Calculate the number of electrons in 4 gram of helium?
#No. of moles of Helium = 4 gm / 4gm = 1 Moles ............,,,,,,,,,,,,


# No of total helium atoms in 1mole is equals to =NA (6.022 * 10^23) .................,,,,,,,,,,,,,,,,,,
.Hence. 1 moles = 1 * NA Helium atoms,...............


# 1 Helium atom has 2 electrons that's mean = 1* NA * 2 electrons = 2 NA electrons.......
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Calculate the number of electrons in 4 gram of helium?
Number of Electrons in 4 grams of Helium

To calculate the number of electrons in 4 grams of helium, we need to consider the atomic structure of helium and its molar mass.

Atomic Structure of Helium:
Helium is a chemical element with the atomic number 2 and symbol He. It belongs to the noble gas group in the periodic table. The atomic structure of helium consists of two protons, two neutrons, and two electrons.

Molar Mass of Helium:
The molar mass of helium is calculated by adding the atomic masses of its constituent particles, which are protons, neutrons, and electrons. The atomic mass of helium is approximately 4.0026 atomic mass units (u).

Calculating the Number of Moles:
To determine the number of electrons in 4 grams of helium, we first need to convert the mass of helium to moles. We can use the molar mass of helium to convert grams to moles using the following equation:

Number of moles = Mass (g) / Molar mass (g/mol)

Substituting the values, we get:

Number of moles = 4 g / 4.0026 g/mol ≈ 0.9998 mol

Avogadro's Number:
Avogadro's number (represented by the symbol Nₐ) is a fundamental constant representing the number of particles (atoms, molecules, or ions) in one mole of a substance. The value of Avogadro's number is approximately 6.022 × 10²³ particles/mol.

Calculating the Number of Electrons:
To calculate the number of electrons, we need to multiply the number of moles by Avogadro's number:

Number of electrons = Number of moles × Avogadro's number

Substituting the values, we get:

Number of electrons = 0.9998 mol × 6.022 × 10²³ electrons/mol ≈ 6.019 × 10²³ electrons

Therefore, there are approximately 6.019 × 10²³ electrons in 4 grams of helium.

Summary:
- Helium has an atomic number of 2 and consists of two protons, two neutrons, and two electrons.
- The molar mass of helium is approximately 4.0026 g/mol.
- To calculate the number of electrons in 4 grams of helium, we convert the mass to moles using the molar mass.
- The number of moles is approximately 0.9998 mol.
- Avogadro's number is approximately 6.022 × 10²³ electrons/mol.
- Multiplying the number of moles by Avogadro's number gives us the number of electrons, which is approximately 6.019 × 10²³ electrons.
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Calculate the number of electrons in 4 gram of helium?
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