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A road embankment 10 m wide at the formation level with side slopes 2:1 and with an average height of 5 m is constructed with an average gradient of 1:40 from the contour 220 m to 280 m. Find the volume of earthwork.
  • a)
    6,40,000 m3
  • b)
    1,40,000 m3
  • c)
    3,40,000 m3
  • d)
    2,40,000 m3
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A road embankment 10 m wide at the formation level with side slopes 2:...
To find the volume of earthwork, we need to calculate the cross-sectional area of the road embankment and then multiply it by the length of the embankment.

Given data:
Width of embankment (W) = 10 m
Side slopes (S) = 2:1
Average height of embankment (H) = 5 m
Average gradient (G) = 1:40
Contour at the start (C1) = 220 m
Contour at the end (C2) = 280 m

1. Calculating the cross-sectional area:
First, we need to calculate the width of the embankment at different heights along the gradient.

At contour C1 (220 m):
Width of embankment at C1 = W + 2HS = 10 + 2(5)(1) = 20 m

At contour C2 (280 m):
Width of embankment at C2 = W + 2HG = 10 + 2(5)(40) = 410 m

Next, we can calculate the average width of the embankment:
Average width = (Width at C1 + Width at C2) / 2 = (20 + 410) / 2 = 215 m

The cross-sectional area (A) can be calculated as:
A = Average width * Length of embankment

2. Calculating the length of the embankment:
The length of the embankment can be calculated using the gradient.
Length = (C2 - C1) / Gradient = (280 - 220) / 40 = 1.5 m

3. Calculating the volume of earthwork:
The volume of earthwork (V) can be calculated as:
V = Cross-sectional area * Length

Substituting the values:
V = 215 * 1.5 = 322.5 m^3

Therefore, the volume of earthwork is approximately 322.5 m^3.

Since this value is not one of the given options, it seems like there might be an error in the given data or options.
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Community Answer
A road embankment 10 m wide at the formation level with side slopes 2:...
Concept:
Gradient: 
A gradient is the rate of rise or falls along the length of the road with respect to horizontal. It is expressed as ‘1' vertical unit to 'N' horizontal units.


 
Area of trapezoidal:
According to the trapezoid area formula, the area of a trapezoid is equal to half the product of the height and the sum of the two bases.
Area = ½ x (Sum of parallel sides) x (perpendicular distance between the parallel sides).
Calculation:

 
Road embankment = 10 m
Average height = 5 m
Difference in elevation(h) = 280 - 220 = 60 m
Average gradient = 1/40
 

L = 2400 m

 
Average cross-sectional area(A) = 12×(10+30)×5
A = 100 m2
Volume of earthwork = A × L
Volume of earthwork = 100 × 2400
∴ Volume of earthwork = 2,40,000 m3
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A road embankment 10 m wide at the formation level with side slopes 2:1 and with an average height of 5 m is constructed with an average gradient of 1:40 from the contour 220 m to 280 m. Find the volume of earthwork.a)6,40,000 m3b)1,40,000 m3c)3,40,000 m3d)2,40,000 m3Correct answer is option 'D'. Can you explain this answer?
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