JEE Exam  >  JEE Questions  >  The shortest distance (in units) between the ... Start Learning for Free
The shortest distance (in units) between the parabolas y2 = 4x and y2=2x−6 is
  • a)
    2
  • b)
    √5
  • c)
    3
  • d)
    none of these
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The shortest distance (in units) between the parabolas y2 = 4x andy2=2...
We can find the distance between the parabolas by finding the distance between their closest points.

First, let's rewrite the equations in terms of y:

y = ±√(4x)

y = ±√(2x)

To find the closest points, we need to set the two equations equal to each other:

±√(4x) = ±√(2x)

Squaring both sides, we get:

4x = 2x

x = 0

Plugging x = 0 into either equation, we get the y-coordinate of the closest point:

y = ±√(0) = 0

Therefore, the closest points are (0,0) on both parabolas.

To find the distance between these points, we can use the distance formula:

d = √[(x2 - x1)2 + (y2 - y1)2]

d = √[(0 - 0)2 + (0 - 0)2]

d = √(0)

d = 0

Therefore, the shortest distance between the parabolas is 0 units.
Free Test
Community Answer
The shortest distance (in units) between the parabolas y2 = 4x andy2=2...
Shortest distance between two curves occurs along the common normal.
Normal to y2=4x at (m2, 2m) is
y+mx−2m−m3=0

Both normals are same,  if  −2m−m3=−4m− 
⇒m=0, ±2
So, points will be (4, 4) and (5, 2) or (4,−4) and (5,−2)
Hence, shortest distance will be
Explore Courses for JEE exam
The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer?
Question Description
The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The shortest distance (in units) between the parabolas y2 = 4x andy2=2x−6 isa)2b)√5c)3d)none of theseCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev