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Two different coils have self inductance 8 mH and 2 mH. The current in both coils are increased at same constant rate. The ratio of the induced emf's in the coil is-
  • a)
    4:1
  • b)
    1:4
  • c)
    1:2
  • d)
    2:1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Two different coils have self inductance 8 mH and 2 mH. The current in...
Concept:
The induced emf in a coil is given by Faraday's law of electromagnetic induction, which states that the induced emf is equal to the rate of change of magnetic flux through the coil. Mathematically, it can be expressed as:

\(\varepsilon = -\frac{{d\Phi}}{{dt}}\)

Where:
- ε is the induced emf
- Φ is the magnetic flux through the coil
- t is the time

The magnetic flux through a coil is given by the product of the magnetic field (B) and the area (A) of the coil. Mathematically, it can be expressed as:

\(\Phi = B \cdot A\)

Since the magnetic field is directly proportional to the current passing through the coil (B ∝ I), we can write:

\(\varepsilon = -\frac{{d(B \cdot A)}}{{dt}} = -B \cdot \frac{{dA}}{{dt}}\) [Using chain rule of differentiation]

Explanation:
Since the current in both coils is increased at the same constant rate, we can assume that the rate of change of current with respect to time is the same for both coils.

Let's consider the induced emf in the first coil (Coil 1) with self-inductance 8 mH. We can write:

\(\varepsilon_1 = -B_1 \cdot \frac{{dA_1}}{{dt}}\) ...(1)

Similarly, for the second coil (Coil 2) with self-inductance 2 mH, we can write:

\(\varepsilon_2 = -B_2 \cdot \frac{{dA_2}}{{dt}}\) ...(2)

Since the rate of change of current with respect to time is the same for both coils, we can write:

\(\frac{{dA_1}}{{dt}} = \frac{{dA_2}}{{dt}}\) ...(3)

Now, let's compare the magnetic fields (B1 and B2) in both coils. The magnetic field is directly proportional to the current passing through the coil. Since the rate of change of current is the same for both coils, we can assume that the currents in both coils are in the same ratio as their self-inductances.

Let the current in Coil 1 be I1 and the current in Coil 2 be I2. We have:

\(\frac{{I_1}}{{I_2}} = \frac{{\text{{Self-inductance of Coil 1}}}}{{\text{{Self-inductance of Coil 2}}}} = \frac{{8 \, \text{{mH}}}}{{2 \, \text{{mH}}}} = 4\) ...(4)

Therefore, we can write:

\(I_1 = 4I_2\) ...(5)

Since the magnetic field is directly proportional to the current, we can write:

\(B_1 = kI_1\) ...(6)

\(B_2 = kI_2\) ...(7)

Where k is a constant of proportionality.

Substituting equations (5), (6), and (7) into equations (1) and (2), we get:

\(\varepsilon_1 = -kI_1 \cdot \frac
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Community Answer
Two different coils have self inductance 8 mH and 2 mH. The current in...

(Since, current is increased at same rate)
 
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Two different coils have self inductance 8 mH and 2 mH. The current in both coils are increased at same constant rate. The ratio of the induced emfs in the coil is-a)4:1b)1:4c)1:2d)2:1Correct answer is option 'A'. Can you explain this answer?
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Two different coils have self inductance 8 mH and 2 mH. The current in both coils are increased at same constant rate. The ratio of the induced emfs in the coil is-a)4:1b)1:4c)1:2d)2:1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two different coils have self inductance 8 mH and 2 mH. The current in both coils are increased at same constant rate. The ratio of the induced emfs in the coil is-a)4:1b)1:4c)1:2d)2:1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two different coils have self inductance 8 mH and 2 mH. The current in both coils are increased at same constant rate. The ratio of the induced emfs in the coil is-a)4:1b)1:4c)1:2d)2:1Correct answer is option 'A'. Can you explain this answer?.
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