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A fixed nuclei of Radium (Z = 88) scattered α-particles through 180o. If the energy of the radiation is 4 MeV, what will be the distance of the closest approach of the scattered α- particles?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A fixed nuclei of Radium (Z = 88) scattered α-particles through 180o. If the energy of the radiation is 4 MeV, what will be the distance of the closest approach of the scattered α- particles?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fixed nuclei of Radium (Z = 88) scattered α-particles through 180o. If the energy of the radiation is 4 MeV, what will be the distance of the closest approach of the scattered α- particles?a)b)c)d)Correct answer is option 'C'. Can you explain this answer?.

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