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A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be?
  • a)
    4450 Ω
  • b)
    5050 Ω
  • c)
    5550 Ω
  • d)
    6050 Ω
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A galvanometer of resistance 50 Ω is connected to a battery of 3...
A galvanometer can be converted into a voltmeter by connecting a high resistance in series with the galvanometer. Let V be the potential difference to be measured by galvanometer. To do so, a resistance R of such a value is connected in series with the galvanometer so that if a potential difference V is applied across the terminals A and B, a current Ig flows through the galvanometer.
Now, total resistance of voltmeter = G + R From Ohm's law, 

Here, The current through the galvanometer

To reduce the deflection from 30 divisions to 20 divisions, the required current

The required resistance R is given by
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A galvanometer of resistance 50 Ω is connected to a battery of 3...
The resistance of a galvanometer is usually given as a range of values, such as 50 ohms +/- 5%. This means that the actual resistance of the galvanometer can vary between 47.5 ohms and 52.5 ohms. The resistance value is important because it affects the sensitivity and accuracy of the galvanometer. A higher resistance allows for a greater voltage drop across the galvanometer, resulting in a larger deflection of the needle. However, a higher resistance also means that the galvanometer draws more current from the circuit being measured, which can affect the accuracy of the measurement. Therefore, the resistance of a galvanometer is typically chosen to balance the desired sensitivity and accuracy for a specific application.
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A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be?a)4450 Ωb)5050 Ωc)5550 Ωd)6050 ΩCorrect answer is option 'A'. Can you explain this answer?
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A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be?a)4450 Ωb)5050 Ωc)5550 Ωd)6050 ΩCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be?a)4450 Ωb)5050 Ωc)5550 Ωd)6050 ΩCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be?a)4450 Ωb)5050 Ωc)5550 Ωd)6050 ΩCorrect answer is option 'A'. Can you explain this answer?.
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