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What is the output of the following code?
def count_permutations(n):
if n == 0:
return 1
else:
return n * count_permutations(n - 1)
def count_permutations(n):
if n == 0:
return 1
else:
return n * count_permutations(n - 1)
def count_partitions(n, k):
if k == 1 or n == k:
return 1
elif k > n:
return 0
else:
return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)
if k == 1 or n == k:
return 1
elif k > n:
return 0
else:
return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)
result = count_permutations(5) % count_partitions(10, 2)
print(result)
print(result)
- a)0
- b)1
- c)5
- d)10
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What is the output of the following code?def count_permutations(n): i...
The code calculates the factorial of 4 using the 'factorial' function. The factorial of a non-negative integer n is the product of all positive integers less than or equal to n. In this case, 4! = 4 * 3 * 2 * 1 = 24.
Most Upvoted Answer
What is the output of the following code?def count_permutations(n): i...
The code provided is incomplete and has a syntax error. It seems that the code is attempting to calculate the number of permutations and partitions.
However, without the complete code and the specific values for `n` and `k`, it is not possible to determine the output.
However, without the complete code and the specific values for `n` and `k`, it is not possible to determine the output.
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What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer?
Question Description
What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer?.
What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer?.
Solutions for What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development.
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What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer?, a detailed solution for What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice What is the output of the following code?def count_permutations(n): if n == 0: return 1 else: return n * count_permutations(n - 1)def count_partitions(n, k): if k == 1 or n == k: return 1 elif k > n: return 0 else: return count_partitions(n - 1, k - 1) + k * count_partitions(n - 1, k)result = count_permutations(5) % count_partitions(10, 2)print(result)a)0b)1c)5d)10Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Software Development tests.
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