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in XeOF4 let x be the total number of bond pairs around Xe y be the total number of lone pairs and z be the total number of 90° angles with respect to angle OXeF then x+y+z is1)212)253)284)26
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in XeOF4 let x be the total number of bond pairs around Xe y be the to...
Explanation:
Xenon tetrafluoride (XeOF4) has a square pyramidal shape, with one lone pair and four bond pairs around the central xenon atom. The lone pair occupies one of the equatorial positions, while the four fluorine atoms occupy the remaining four positions.
Determining x, y, and z:
- x: The number of bond pairs around Xe is 4. This can be determined by counting the number of Xe-F bonds.
- y: The number of lone pairs around Xe is 1. This can be determined by subtracting the number of bond pairs from the total number of electron pairs around Xe, which is 5.
- z: The number of 90° angles with respect to O-Xe-F is 2. This can be determined by looking at the structure of XeOF4 and counting the number of positions where two fluorine atoms are 90° apart.
Therefore, x y z is equal to 4 1 2, which is option (1) 21.
Summary:
- XeOF4 has a square pyramidal shape.
- The number of bond pairs around Xe is 4.
- The number of lone pairs around Xe is 1.
- The number of 90° angles with respect to O-Xe-F is 2.
- Therefore, x y z is 4 1 2.
Xenon tetrafluoride (XeOF4) has a square pyramidal shape, with one lone pair and four bond pairs around the central xenon atom. The lone pair occupies one of the equatorial positions, while the four fluorine atoms occupy the remaining four positions.
Determining x, y, and z:
- x: The number of bond pairs around Xe is 4. This can be determined by counting the number of Xe-F bonds.
- y: The number of lone pairs around Xe is 1. This can be determined by subtracting the number of bond pairs from the total number of electron pairs around Xe, which is 5.
- z: The number of 90° angles with respect to O-Xe-F is 2. This can be determined by looking at the structure of XeOF4 and counting the number of positions where two fluorine atoms are 90° apart.
Therefore, x y z is equal to 4 1 2, which is option (1) 21.
Summary:
- XeOF4 has a square pyramidal shape.
- The number of bond pairs around Xe is 4.
- The number of lone pairs around Xe is 1.
- The number of 90° angles with respect to O-Xe-F is 2.
- Therefore, x y z is 4 1 2.
Community Answer
in XeOF4 let x be the total number of bond pairs around Xe y be the to...
X = 6 ,
y = 16, Count the lone pairs of all the atoms in the compound.
z = 4 as all the XeF bonds are at 90 degree to the OXeF bond.
Therefore, x+y+z= 26
y = 16, Count the lone pairs of all the atoms in the compound.
z = 4 as all the XeF bonds are at 90 degree to the OXeF bond.
Therefore, x+y+z= 26
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in XeOF4 let x be the total number of bond pairs around Xe y be the total number of lone pairs and z be the total number of 90° angles with respect to angle OXeF then x+y+z is1)212)253)284)26
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