In photoelectric effect if the intensity of light is doubled then maxi...
Explanation:
The photoelectric effect is the process in which electrons are emitted from a metal surface when light falls on it. The maximum kinetic energy of the photoelectrons depends on the frequency of the incident light and the work function of the metal. Work function is the minimum energy required to remove an electron from the metal surface.
When the intensity of light is increased, the number of photons falling on the metal surface increases. However, the energy of each photon remains the same. Therefore, increasing the intensity of light does not increase the energy of the photons. This means that the maximum kinetic energy of the photoelectrons will remain the same.
Mathematical Explanation:
The maximum kinetic energy of the photoelectrons is given by the equation:
Kmax = hf - Φ
where h is the Planck's constant, f is the frequency of the incident light, and Φ is the work function of the metal.
Doubling the intensity of light means doubling the number of photons falling on the metal surface. The total energy of the photons falling on the metal surface will be:
E = nhf
where n is the number of photons falling per unit time.
However, the energy of each photon remains the same, i.e., hf. Therefore, the frequency of the incident light remains the same. This means that the maximum kinetic energy of the photoelectrons will remain the same.
Therefore, option D is the correct answer.