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The resistance of a conducting wire at a temperature of 27oC is found to be 1. If the temperature coefficient of the wire is given to be (1.25 × 10-3)°C-1, at what temperature will the resistance of the wire be 2Ω?
- a)854oC
- b)970oC
- c)1000oC
- d)1150oC
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
The resistance of a conducting wire at a temperature of 27oC is found ...
-3) / oC, then what will be the resistance of the wire at a temperature of 50oC?
To find the resistance at a different temperature, we can use the formula:
R2 = R1 * (1 + α * (T2 - T1))
Where:
R2 = resistance at the second temperature
R1 = resistance at the first temperature
α = temperature coefficient of the wire
T2 = second temperature
T1 = first temperature
Given:
R1 = 1
α = (1.25 * 10^-3) / oC
T1 = 27oC
T2 = 50oC
Plugging in the values:
R2 = 1 * (1 + (1.25 * 10^-3) * (50 - 27))
R2 = 1 * (1 + (1.25 * 10^-3) * 23)
R2 = 1 * (1 + 0.02875)
R2 = 1 * 1.02875
R2 = 1.02875
Therefore, the resistance of the wire at a temperature of 50oC is approximately 1.02875.
To find the resistance at a different temperature, we can use the formula:
R2 = R1 * (1 + α * (T2 - T1))
Where:
R2 = resistance at the second temperature
R1 = resistance at the first temperature
α = temperature coefficient of the wire
T2 = second temperature
T1 = first temperature
Given:
R1 = 1
α = (1.25 * 10^-3) / oC
T1 = 27oC
T2 = 50oC
Plugging in the values:
R2 = 1 * (1 + (1.25 * 10^-3) * (50 - 27))
R2 = 1 * (1 + (1.25 * 10^-3) * 23)
R2 = 1 * (1 + 0.02875)
R2 = 1 * 1.02875
R2 = 1.02875
Therefore, the resistance of the wire at a temperature of 50oC is approximately 1.02875.
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Community Answer
The resistance of a conducting wire at a temperature of 27oC is found ...
As we know,
Rt = Ro (1 + αt)
Let R1 = Resistance at temperature 27oC
And R2 = Resistance at temperature t2
Therefore,
This is our required solution.
Rt = Ro (1 + αt)
Let R1 = Resistance at temperature 27oC
And R2 = Resistance at temperature t2
Therefore,
This is our required solution.
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