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Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest?
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Two identical charges +q are fixed at points A Nd B at a distance 2a a...
Problem Statement:
Two charges +q are fixed at points A and B at a distance 2a apart. A third particle with charge -q and mass M is thrown with a speed u at point C. From the midpoint C, we need to find the maximum distance this particle will travel before coming to rest.
Solution:
- Initial Analysis: Initially, the particle at C will experience a force from both charges at A and B, leading to an acceleration. As it moves towards A or B, the force from the opposite charge will decrease until it eventually comes to rest.
- Calculating Force: The force on the particle at C due to the charge at A is k*q*q/(2a)^2 and in the same way due to the charge at B is k*q*q/(2a)^2. The net force can be calculated by summing these two forces.
- Calculating Acceleration: Using Newton's second law, F = m*a, we can find the acceleration of the particle. The acceleration will be maximum at the midpoint C.
- Calculating Distance: To find the maximum distance traveled by the particle, we can use the equation of motion, v^2 = u^2 + 2*a*s, where v is the final velocity (0 m/s), u is the initial velocity, a is acceleration, and s is the distance traveled.
- Substitute Values: Substitute the known values into the equation and solve for s to find the maximum distance the particle will travel before coming to rest.
- Final Answer: The maximum distance the particle will travel can be calculated using the above steps.
Two charges +q are fixed at points A and B at a distance 2a apart. A third particle with charge -q and mass M is thrown with a speed u at point C. From the midpoint C, we need to find the maximum distance this particle will travel before coming to rest.
Solution:
- Initial Analysis: Initially, the particle at C will experience a force from both charges at A and B, leading to an acceleration. As it moves towards A or B, the force from the opposite charge will decrease until it eventually comes to rest.
- Calculating Force: The force on the particle at C due to the charge at A is k*q*q/(2a)^2 and in the same way due to the charge at B is k*q*q/(2a)^2. The net force can be calculated by summing these two forces.
- Calculating Acceleration: Using Newton's second law, F = m*a, we can find the acceleration of the particle. The acceleration will be maximum at the midpoint C.
- Calculating Distance: To find the maximum distance traveled by the particle, we can use the equation of motion, v^2 = u^2 + 2*a*s, where v is the final velocity (0 m/s), u is the initial velocity, a is acceleration, and s is the distance traveled.
- Substitute Values: Substitute the known values into the equation and solve for s to find the maximum distance the particle will travel before coming to rest.
- Final Answer: The maximum distance the particle will travel can be calculated using the above steps.
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Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest?
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Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest?.
Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical charges +q are fixed at points A Nd B at a distance 2a apart . the third particle with charge -q as Nd mass M is thrown with a speed u at point C .From the mid point C find the max. distance this particle will travel before coming to rest?.
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