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A car of mass 1000 kg is moving at a velocity of 20 m/s. Suddenly, the driver applies the brakes, and the car comes to a stop in 4 seconds. What is the magnitude of the average force exerted by the brakes on the car? (Assume no external forces are acting on the car)

  • a)
    5000 N

  • b)
    250 N

  • c)
    1000 N

  • d)
    2000 N

Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A car of mass 1000 kg is moving at a velocity of 20 m/s. Suddenly, the...
Solution:

Given:

Mass of the car, m = 1000 kg

Initial velocity, u = 20 m/s

Final Velocity, v = 0 (since the car comes to a stop)

Time taken, t = 4 s

Acceleration, a = ?

Force, F = ?

Using the kinematic equation,
v = u + at
0 = 20 + a × 4
a = -5 m/s² (negative because the car is decelerating)

Using Newton's second law of motion,
F = ma
F = 1000 kg × (-5 m/s²)
F = -5000 N (negative because the force is acting opposite to the direction of motion)

Taking the magnitude of force,
F = 5000 N

Therefore, the magnitude of the average force exerted by the brakes on the car is 500 N.

Option (a) is the correct answer.
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Community Answer
A car of mass 1000 kg is moving at a velocity of 20 m/s. Suddenly, the...
Given:
Mass of the car (m) = 1000 kg
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 m/s
Time (t) = 4 s
Using the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can rearrange the equation to solve for the acceleration.
0 = 20 m/s + a * 4 s
a = -5 m/s² (negative sign indicates deceleration)
Since the car comes to a stop, its final velocity is 0 m/s. We can use Newton's second law, F = ma, where F is the force, m is the mass, and a is the acceleration, to find the magnitude of the force.
F = 1000 kg * (-5 m/s²)
F = -5000 N
The magnitude of the force is 5000 N. However, since the force is acting in the opposite direction to the car's motion (deceleration), we take the magnitude as the answer.
Therefore, the correct answer is A: 500 N.
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