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G is the centroid of ΔABC. If AG = BC, then ∠BGC is     (SSC Sub. Ins. 2012)
  • a)
    60°
  • b)
    120°
  • c)
    90°
  • d)
    30°
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
G is the centroid of ΔABC. If AG = BC, then ∠BGC is (SSC Su...

AG = BC (Given)
BD = DC (given) and AD is median

So, GD = BD = DC
ΔBGD & ΔGCD are both isosceles D.
Then ∠BGC = ∠BGD + ∠CGD = 90°
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G is the centroid of ΔABC. If AG = BC, then ∠BGC is (SSC Sub. Ins. 2012)a)60°b)120°c)90°d)30°Correct answer is option 'C'. Can you explain this answer?
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