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The price of an article was first increased by 10% and then again by 20%. If the last increased price be ₹ 33, the original price was      (SSC CGL 2nd Sit. 2010)
  • a)
    ₹ 30
  • b)
    ₹ 27.50
  • c)
    ₹ 26.50
  • d)
    ₹ 25
Correct answer is option 'D'. Can you explain this answer?
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The price of an article was first increased by 10% and then again by 2...
Question:
The price of an article was first increased by 10% and then again by 20%. If the last increased price is 33, what was the original price?

Solution:

Let's assume the original price of the article is x.

First Increase:
The price is increased by 10%. Therefore, the new price after the first increase is:
x + (10% of x) = x + 0.1x = 1.1x

Second Increase:
The new price after the first increase is 1.1x, and it is increased by 20%. Therefore, the final price after the second increase is:
1.1x + (20% of 1.1x) = 1.1x + 0.22x = 1.32x

According to the question, the final price after the second increase is 33. Therefore, we can set up the equation:

1.32x = 33

Solving the Equation:
To find the original price (x), we need to solve the equation:

1.32x = 33

Dividing both sides of the equation by 1.32:
x = 33 / 1.32
x = 25

Therefore, the original price of the article was 25.

Answer:
The original price was 25. (Option D)
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The price of an article was first increased by 10% and then again by 20%. If the last increased price be 33, the original price was (SSC CGL 2nd Sit. 2010)a)30b)27.50c)26.50d)25Correct answer is option 'D'. Can you explain this answer?
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