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Which of the following traversal techniques visits the left subtree, then the root, and finally the right subtree?
- a)Inorder traversal.
- b)Preorder traversal.
- c)Postorder traversal.
- d)Level order traversal.
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Which of the following traversal techniques visits the left subtree, t...
Inorder traversal visits the left subtree, then the root, and finally the right subtree. It is a depth-first traversal technique that follows the left-root-right order. In this traversal, all nodes are visited in ascending order if the tree is a binary search tree.
Here is a step-by-step explanation of how inorder traversal works:
1. Visit the left subtree: Start from the root node and recursively traverse the left subtree until you reach a leaf node (a node with no children).
2. Visit the root: Once you reach a leaf node or a node with no left child, visit the current node.
3. Visit the right subtree: After visiting the root node, recursively traverse the right subtree following the same order: left subtree, root, and right subtree.
This process continues until all nodes in the tree have been visited.
Example:
Let's consider a binary tree with the following structure:
```
1
/ \
2 3
/ \
4 5
```
The inorder traversal of this tree would be: 4 -> 2 -> 5 -> 1 -> 3.
Explanation of the traversal:
1. Start at the root node (1).
2. Visit the left subtree (2).
3. Visit the left subtree of node 2 (4).
4. No more left child of node 4, so visit node 4.
5. No more right child of node 4, so go back to node 2.
6. Visit node 2.
7. Visit the right subtree of node 2 (5).
8. Visit node 5.
9. No more left or right child of node 5, so go back to node 1.
10. Visit node 1.
11. Visit the right subtree of node 1 (3).
12. No more left child of node 3, so visit node 3.
13. No more right child of node 3, so traversal is complete.
Therefore, the inorder traversal of the given tree is 4 -> 2 -> 5 -> 1 -> 3.
In conclusion, the correct answer is option 'A' (Inorder traversal) as it visits the left subtree, then the root, and finally the right subtree.
Here is a step-by-step explanation of how inorder traversal works:
1. Visit the left subtree: Start from the root node and recursively traverse the left subtree until you reach a leaf node (a node with no children).
2. Visit the root: Once you reach a leaf node or a node with no left child, visit the current node.
3. Visit the right subtree: After visiting the root node, recursively traverse the right subtree following the same order: left subtree, root, and right subtree.
This process continues until all nodes in the tree have been visited.
Example:
Let's consider a binary tree with the following structure:
```
1
/ \
2 3
/ \
4 5
```
The inorder traversal of this tree would be: 4 -> 2 -> 5 -> 1 -> 3.
Explanation of the traversal:
1. Start at the root node (1).
2. Visit the left subtree (2).
3. Visit the left subtree of node 2 (4).
4. No more left child of node 4, so visit node 4.
5. No more right child of node 4, so go back to node 2.
6. Visit node 2.
7. Visit the right subtree of node 2 (5).
8. Visit node 5.
9. No more left or right child of node 5, so go back to node 1.
10. Visit node 1.
11. Visit the right subtree of node 1 (3).
12. No more left child of node 3, so visit node 3.
13. No more right child of node 3, so traversal is complete.
Therefore, the inorder traversal of the given tree is 4 -> 2 -> 5 -> 1 -> 3.
In conclusion, the correct answer is option 'A' (Inorder traversal) as it visits the left subtree, then the root, and finally the right subtree.
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Community Answer
Which of the following traversal techniques visits the left subtree, t...
In the implementation of a binary tree in C++, the NULL keyword is used to represent an empty node or a null pointer.
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Which of the following traversal techniques visits the left subtree, then the root, and finally the right subtree?a)Inorder traversal.b)Preorder traversal.c)Postorder traversal.d)Level order traversal.Correct answer is option 'A'. Can you explain this answer?
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