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Code and Output:
#include <iostream>
using namespace std;
struct Node {
   int data;
   Node* left;
   Node* right;
};
int sumOfLeafNodes(Node* root) {
   if (root == NULL)
      return 0;
   if (root->left == NULL && root->right == NULL)
      return root->data;
   return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);
}
int main() {
   Node* root = new Node();
   root->data = 10;
   root->left = new Node();
   root->left->data = 20;
   root->right = new Node();
   root->right->data = 30;
   root->left->left = new Node();
   root->left->left->data = 40;
   root->left->right = new Node();
   root->left->right->data = 50;
   cout << sumOfLeafNodes(root) << endl;
   return 0;
}
What will be the output of the above code?
  • a)
    10
  • b)
    40
  • c)
    50
  • d)
    120
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Code and Output:#include <iostream>using namespace std;struct No...
The code defines a function 'sumOfLeafNodes' that calculates the sum of leaf nodes in a binary tree. The tree is created with five nodes, and the leaf nodes have values 40 and 50. Therefore, the sum of leaf nodes is 40 + 50 = 90.
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Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer?
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Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer? for Software Development 2024 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer?.
Solutions for Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development. Download more important topics, notes, lectures and mock test series for Software Development Exam by signing up for free.
Here you can find the meaning of Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};int sumOfLeafNodes(Node* root) { if (root == NULL) return 0; if (root->left == NULL && root->right == NULL) return root->data; return sumOfLeafNodes(root->left) + sumOfLeafNodes(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; root->left->left = new Node(); root->left->left->data = 40; root->left->right = new Node(); root->left->right->data = 50; cout << sumOfLeafNodes(root) << endl; return 0;}What will be the output of the above code?a)10b)40c)50d)120Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Software Development tests.
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