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Given a stack st with elements [1, 2, 3, 4, 5], what will be the value of x after the following code execution?
#include <iostream>
#include <stack>
using namespace std;
int main() {
   stack<int> st;
   st.push(1);
   st.push(2);
   st.push(3);
   int x = st.top();
   st.pop();
   x += st.top();
   return 0;
}
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Given a stack st with elements [1, 2, 3, 4, 5], what will be the value...
The code stores the value at the top of the stack (3) in variable x. Then, it pops an element from the stack and adds its value (2) to x. Therefore, x becomes 3 + 2 = 5.
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Given a stack st with elements [1, 2, 3, 4, 5], what will be the value of x after the following code execution?#include <iostream>#include <stack>using namespace std;int main() { stack<int> st; st.push(1); st.push(2); st.push(3); int x = st.top(); st.pop(); x += st.top(); return 0;}a)1b)2c)3d)4Correct answer is option 'D'. Can you explain this answer?
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