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Consider the following SQL code:
CREATE TABLE books (
book_id INT PRIMARY KEY,
book_name VARCHAR(50),
author VARCHAR(50),
price DECIMAL(10, 2)
);
book_id INT PRIMARY KEY,
book_name VARCHAR(50),
author VARCHAR(50),
price DECIMAL(10, 2)
);
INSERT INTO books (book_id, book_name, author, price)
VALUES (1, 'Book1', 'Author1', 10.99),
(2, 'Book2', 'Author2', 20.99),
(3, 'Book3', 'Author1', 15.99);
VALUES (1, 'Book1', 'Author1', 10.99),
(2, 'Book2', 'Author2', 20.99),
(3, 'Book3', 'Author1', 15.99);
SELECT COUNT(DISTINCT author) FROM books;
What will be the output of the SELECT statement?
- a)1
- b)2
- c)3
- d)Error: Table 'books' doesn't exist.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMA...
The SELECT statement counts the number of distinct authors from the books table, which is 2 ('Author1' and 'Author2').
Most Upvoted Answer
Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMA...
Answer:
The output of the SELECT statement will be 2.
Here's the explanation:
- The given SQL code creates a table named "books" with four columns: book_id, book_name, author, and price.
- The book_id column is set as the primary key of the table, ensuring uniqueness for each book.
- The price column is set as a decimal with a precision of 10 and scale of 2, allowing for a maximum of 10 digits with 2 decimal places.
- The INSERT statement adds three rows of data into the "books" table, specifying values for the book_id, book_name, author, and price columns.
- The SELECT statement with the COUNT and DISTINCT functions is used to retrieve the count of distinct authors in the "books" table.
- The DISTINCT keyword eliminates duplicate values, so only unique authors are counted.
- In the given example, there are three rows in the "books" table with two distinct authors (Author1 and Author2).
- Therefore, the output of the SELECT statement will be 2.
Summary:
- The SQL code creates a table named "books" and inserts three rows of data into it.
- The SELECT statement with the COUNT and DISTINCT functions retrieves the count of distinct authors in the "books" table.
- The output of the SELECT statement will be 2, indicating that there are two distinct authors in the "books" table.
The output of the SELECT statement will be 2.
Here's the explanation:
- The given SQL code creates a table named "books" with four columns: book_id, book_name, author, and price.
- The book_id column is set as the primary key of the table, ensuring uniqueness for each book.
- The price column is set as a decimal with a precision of 10 and scale of 2, allowing for a maximum of 10 digits with 2 decimal places.
- The INSERT statement adds three rows of data into the "books" table, specifying values for the book_id, book_name, author, and price columns.
- The SELECT statement with the COUNT and DISTINCT functions is used to retrieve the count of distinct authors in the "books" table.
- The DISTINCT keyword eliminates duplicate values, so only unique authors are counted.
- In the given example, there are three rows in the "books" table with two distinct authors (Author1 and Author2).
- Therefore, the output of the SELECT statement will be 2.
Summary:
- The SQL code creates a table named "books" and inserts three rows of data into it.
- The SELECT statement with the COUNT and DISTINCT functions retrieves the count of distinct authors in the "books" table.
- The output of the SELECT statement will be 2, indicating that there are two distinct authors in the "books" table.
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Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMARY KEY, book_name VARCHAR(50), author VARCHAR(50), price DECIMAL(10, 2));INSERT INTO books (book_id, book_name, author, price)VALUES (1, Book1, Author1, 10.99), (2, Book2, Author2, 20.99), (3, Book3, Author1, 15.99);SELECT COUNT(DISTINCT author) FROM books;What will be the output of the SELECT statement?a)1b)2c)3d)Error: Table books doesnt exist.Correct answer is option 'B'. Can you explain this answer?
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Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMARY KEY, book_name VARCHAR(50), author VARCHAR(50), price DECIMAL(10, 2));INSERT INTO books (book_id, book_name, author, price)VALUES (1, Book1, Author1, 10.99), (2, Book2, Author2, 20.99), (3, Book3, Author1, 15.99);SELECT COUNT(DISTINCT author) FROM books;What will be the output of the SELECT statement?a)1b)2c)3d)Error: Table books doesnt exist.Correct answer is option 'B'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMARY KEY, book_name VARCHAR(50), author VARCHAR(50), price DECIMAL(10, 2));INSERT INTO books (book_id, book_name, author, price)VALUES (1, Book1, Author1, 10.99), (2, Book2, Author2, 20.99), (3, Book3, Author1, 15.99);SELECT COUNT(DISTINCT author) FROM books;What will be the output of the SELECT statement?a)1b)2c)3d)Error: Table books doesnt exist.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMARY KEY, book_name VARCHAR(50), author VARCHAR(50), price DECIMAL(10, 2));INSERT INTO books (book_id, book_name, author, price)VALUES (1, Book1, Author1, 10.99), (2, Book2, Author2, 20.99), (3, Book3, Author1, 15.99);SELECT COUNT(DISTINCT author) FROM books;What will be the output of the SELECT statement?a)1b)2c)3d)Error: Table books doesnt exist.Correct answer is option 'B'. Can you explain this answer?.
Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMARY KEY, book_name VARCHAR(50), author VARCHAR(50), price DECIMAL(10, 2));INSERT INTO books (book_id, book_name, author, price)VALUES (1, Book1, Author1, 10.99), (2, Book2, Author2, 20.99), (3, Book3, Author1, 15.99);SELECT COUNT(DISTINCT author) FROM books;What will be the output of the SELECT statement?a)1b)2c)3d)Error: Table books doesnt exist.Correct answer is option 'B'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMARY KEY, book_name VARCHAR(50), author VARCHAR(50), price DECIMAL(10, 2));INSERT INTO books (book_id, book_name, author, price)VALUES (1, Book1, Author1, 10.99), (2, Book2, Author2, 20.99), (3, Book3, Author1, 15.99);SELECT COUNT(DISTINCT author) FROM books;What will be the output of the SELECT statement?a)1b)2c)3d)Error: Table books doesnt exist.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE books ( book_id INT PRIMARY KEY, book_name VARCHAR(50), author VARCHAR(50), price DECIMAL(10, 2));INSERT INTO books (book_id, book_name, author, price)VALUES (1, Book1, Author1, 10.99), (2, Book2, Author2, 20.99), (3, Book3, Author1, 15.99);SELECT COUNT(DISTINCT author) FROM books;What will be the output of the SELECT statement?a)1b)2c)3d)Error: Table books doesnt exist.Correct answer is option 'B'. Can you explain this answer?.
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