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What will be the output of the following code?
#include <iostream>
class Base {
public:
    int x;
    Base() {
        x = 0;
    }
    virtual void display() {
        std::cout << "x = " << x << std::endl;
    }
};
class Derived : public Base {
public:
    Derived() {
        x = 5;
    }
    void display() {
        std::cout << "x = " << x << std::endl;
    }
};
int main() {
    Base* bptr = new Derived();
    bptr->display();
    delete bptr;
    return 0;
}
  • a)
    x = 0
  • b)
    x = 5
  • c)
    Compile-time error
  • d)
    Runtime error
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following code?#include <iostream>...
The code creates a dynamic object of the derived class "Derived" using a base class pointer ("Base* bptr = new Derived();"). When the "display" function is called through the base class pointer, it invokes the overridden function in the derived class, printing "x = 5". The object is properly deallocated using "delete" at the end.
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What will be the output of the following code?#include <iostream>class Base {public: int x; Base() { x = 0; } virtual void display() { std::cout << "x = " << x << std::endl; }};class Derived : public Base {public: Derived() { x = 5; } void display() { std::cout << "x = " << x << std::endl; }};int main() { Base* bptr = new Derived(); bptr->display(); delete bptr; return 0;}a)x = 0b)x = 5c)Compile-time errord)Runtime errorCorrect answer is option 'B'. Can you explain this answer?
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What will be the output of the following code?#include <iostream>class Base {public: int x; Base() { x = 0; } virtual void display() { std::cout << "x = " << x << std::endl; }};class Derived : public Base {public: Derived() { x = 5; } void display() { std::cout << "x = " << x << std::endl; }};int main() { Base* bptr = new Derived(); bptr->display(); delete bptr; return 0;}a)x = 0b)x = 5c)Compile-time errord)Runtime errorCorrect answer is option 'B'. Can you explain this answer? for Software Development 2024 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about What will be the output of the following code?#include <iostream>class Base {public: int x; Base() { x = 0; } virtual void display() { std::cout << "x = " << x << std::endl; }};class Derived : public Base {public: Derived() { x = 5; } void display() { std::cout << "x = " << x << std::endl; }};int main() { Base* bptr = new Derived(); bptr->display(); delete bptr; return 0;}a)x = 0b)x = 5c)Compile-time errord)Runtime errorCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Software Development 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the output of the following code?#include <iostream>class Base {public: int x; Base() { x = 0; } virtual void display() { std::cout << "x = " << x << std::endl; }};class Derived : public Base {public: Derived() { x = 5; } void display() { std::cout << "x = " << x << std::endl; }};int main() { Base* bptr = new Derived(); bptr->display(); delete bptr; return 0;}a)x = 0b)x = 5c)Compile-time errord)Runtime errorCorrect answer is option 'B'. Can you explain this answer?.
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