Class 12 Exam  >  Class 12 Questions  >  Differentiation of y = tan(x+y) Start Learning for Free
Differentiation of y = tan(x+y)
Most Upvoted Answer
Differentiation of y = tan(x+y)
Community Answer
Differentiation of y = tan(x+y)
**Differentiation of y = tan(x y)**

To find the derivative of the function y = tan(xy), we will use the chain rule. The chain rule is a method for finding the derivative of composite functions, which are functions that can be expressed as the composition of two or more functions.

**Using the Chain Rule:**

The chain rule states that if we have a composite function f(g(x)), then the derivative of f(g(x)) with respect to x is given by:

(dy/dx) = (dy/du) * (du/dx)

Where u = g(x) and y = f(u).

**Applying the Chain Rule:**

In our case, we have the composite function y = tan(xy), where u = xy and y = tan(u). Let's differentiate each part separately:

1. Differentiating y = tan(u) with respect to u:
- The derivative of tan(u) with respect to u is sec^2(u). This can be derived from the basic trigonometric identity: d/dx(tan(x)) = sec^2(x).

2. Differentiating u = xy with respect to x:
- To differentiate u = xy, we treat y as a constant because we are differentiating with respect to x. So, the derivative of u with respect to x is simply y.

Now, we can apply the chain rule:

(dy/dx) = (dy/du) * (du/dx)
= sec^2(u) * y

Substituting u = xy, we get:

(dy/dx) = sec^2(xy) * y

Therefore, the derivative of y = tan(xy) with respect to x is sec^2(xy) * y.

**Summary:**

The derivative of y = tan(xy) with respect to x is given by dy/dx = sec^2(xy) * y. We used the chain rule to differentiate the composite function y = tan(xy) by differentiating the inner function and the outer function separately. Finally, we substituted the value of the inner function (u = xy) into the derivative expression.
Explore Courses for Class 12 exam
Differentiation of y = tan(x+y)
Question Description
Differentiation of y = tan(x+y) for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Differentiation of y = tan(x+y) covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Differentiation of y = tan(x+y) .
Solutions for Differentiation of y = tan(x+y) in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Differentiation of y = tan(x+y) defined & explained in the simplest way possible. Besides giving the explanation of Differentiation of y = tan(x+y) , a detailed solution for Differentiation of y = tan(x+y) has been provided alongside types of Differentiation of y = tan(x+y) theory, EduRev gives you an ample number of questions to practice Differentiation of y = tan(x+y) tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev