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A continuous beam ABC of UDL 4.5KN/m with Length AB 3m and BC 1m. Find the distance of the point of contraflexure P from support B. The reaction at A 6KN and B 12KN.
1. 0.25m
2 1.5m
3. 2.67 m
4. 0.33m?
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A continuous beam ABC of UDL 4.5KN/m with Length AB 3m and BC 1m. Fin...
To find the distance of the point of contraflexure P from support B in a continuous beam with a uniformly distributed load (UDL), we can use the equation for the bending moment at any point along the beam.

1. **Understanding the problem:**
- We have a continuous beam ABC with a UDL of 4.5 kN/m.
- The length AB is 3m and BC is 1m.
- The reaction at support A is 6 kN and at support B is 12 kN.
- We need to find the distance of the point of contraflexure P from support B.

2. **Calculating the reaction at support C:**
- To calculate the reaction at support C, we need to consider the equilibrium of forces.
- The total load on the beam is the UDL multiplied by the length of AB (4.5 kN/m * 3m = 13.5 kN).
- The total load on the beam is distributed between supports A and C.
- The sum of the reactions at A and C should be equal to the total load on the beam.
- Thus, the reaction at C can be calculated as 13.5 kN - 6 kN = 7.5 kN.

3. **Calculating the bending moment at point P:**
- To calculate the bending moment at point P, we need to consider the beam's response to the applied loads.
- The bending moment at any point on the beam can be calculated using the equation M = wL^2/8, where M is the bending moment, w is the UDL, and L is the length of the beam segment.
- The bending moment at point P can be calculated using the equation M_p = w_AB * L_AB^2/8 + w_BC * L_BC^2/8, where w_AB is the UDL on segment AB, L_AB is the length of segment AB, w_BC is the UDL on segment BC, and L_BC is the length of segment BC.
- Plugging in the values, we get M_p = 4.5 kN/m * 3m * 3m / 8 + 4.5 kN/m * 1m * 1m / 8 = 30.375 kNm.

4. **Calculating the distance of point P from support B:**
- The point of contraflexure occurs where the bending moment changes sign, i.e., from positive to negative or vice versa.
- At the point of contraflexure, the bending moment is zero.
- So, we can set M_p = 0 and solve for the distance of point P from support B.
- 30.375 kNm = 0.33m * 4.5 kN/m * 3m * 3m / 8 + 4.5 kN/m * 1m * 1m / 8
- Simplifying the equation, we get 30.375 kNm = 0.33m * 30.375 kNm
- Dividing both sides by 30.375 kNm, we get 0.33m = 1.
- Therefore, the distance of point P from support B is 0.33m.

5. **Conclusion:**
- The distance of the point of contraflexure P from support B in the continuous
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A continuous beam ABC of UDL 4.5KN/m with Length AB 3m and BC 1m. Find the distance of the point of contraflexure P from support B. The reaction at A 6KN and B 12KN.1. 0.25m2 1.5m3. 2.67 m4. 0.33m?
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A continuous beam ABC of UDL 4.5KN/m with Length AB 3m and BC 1m. Find the distance of the point of contraflexure P from support B. The reaction at A 6KN and B 12KN.1. 0.25m2 1.5m3. 2.67 m4. 0.33m? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A continuous beam ABC of UDL 4.5KN/m with Length AB 3m and BC 1m. Find the distance of the point of contraflexure P from support B. The reaction at A 6KN and B 12KN.1. 0.25m2 1.5m3. 2.67 m4. 0.33m? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A continuous beam ABC of UDL 4.5KN/m with Length AB 3m and BC 1m. Find the distance of the point of contraflexure P from support B. The reaction at A 6KN and B 12KN.1. 0.25m2 1.5m3. 2.67 m4. 0.33m?.
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