In a smooth pipe of uniform diameter 10cm, it is recorded that an elev...
**Direction of Flow**
To determine the direction of flow between section A and B, we need to compare the pressures at each section. In this case, the pressure at section A is 55 kPa, while the pressure at section B is 30 kPa. Since the pressure at section B is lower than at section A, the flow will be from section A to section B.
**Total Head Loss**
The total head loss in a pipe can be calculated using the Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at different points in a pipe. The equation is given as:
Total head loss = (P1 - P2) / ρg + (V1^2 - V2^2) / 2g + (Z1 - Z2)
Where:
P1 and P2 are the pressures at sections A and B, respectively
ρ is the density of the fluid
g is the acceleration due to gravity
V1 and V2 are the velocities at sections A and B, respectively
Z1 and Z2 are the elevations at sections A and B, respectively
In this case, the density of the fluid is not given, but we can assume it to be water, which has a density of approximately 1000 kg/m³. The acceleration due to gravity is 9.8 m/s².
Substituting the given values into the equation, we have:
P1 = 55 kPa = 55,000 Pa
P2 = 30 kPa = 30,000 Pa
Z1 = 15 m
Z2 = 20 m
V1 = 1000 liters/s = 1 m³/s
Plugging these values into the equation, we get:
Total head loss = (55,000 - 30,000) / (1000 * 1000) + (1^2 - V2^2) / (2 * 9.8) + (15 - 20)
Simplifying the equation, we have:
Total head loss = 25,000 / (1000 * 1000) + (1 - V2^2) / (2 * 9.8) - 5
Since the flow rate is given as 1000 liters/s, we know that V1 = 1 m³/s. Therefore, we can substitute V1 into the equation:
Total head loss = 25,000 / (1000 * 1000) + (1 - V2^2) / (2 * 9.8) - 5
Now, we can solve this equation to find the value of V2 and subsequently calculate the total head loss.
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