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A moving coil galvanometer has a resistance of 50 Ω and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?
- a)50/99 Ω in series
- b)50/99 Ω in parallel
- c)0.01 Ω in series
- d)0.01 Ω in parallel
Correct answer is option 'B'. Can you explain this answer?
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A moving coil galvanometer has a resistance of 50 and gives full scal...
To convert a moving coil galvanometer into an ammeter with a full-scale deflection for 1A, we need to connect a shunt resistance in parallel with the galvanometer. This shunt resistance will provide an alternative path for the majority of the current, allowing only a fraction of the total current to pass through the galvanometer.
Let's consider the given specifications:
- Resistance of the moving coil galvanometer: 50Ω
- Full-scale deflection current of the galvanometer: 10mA
- Desired full-scale deflection current for the ammeter: 1A
To calculate the required shunt resistance, we can use the formula:
Rs = (Rg * Ia) / (Ig - Ia)
Where:
- Rs is the shunt resistance
- Rg is the resistance of the galvanometer
- Ia is the desired full-scale deflection current for the ammeter
- Ig is the full-scale deflection current of the galvanometer
Substituting the given values into the formula, we have:
Rs = (50Ω * 1A) / (10mA - 1A)
Simplifying the expression, we get:
Rs = (50Ω * 1A) / (0.01A - 1A)
Rs = 50Ω / (-0.99A)
Rs ≈ -50.505Ω
Since resistance cannot be negative, we take the absolute value of Rs:
Rs ≈ 50.505Ω
In order to achieve full-scale deflection for 1A, we need to connect a shunt resistance of approximately 50.505Ω in parallel with the galvanometer.
Among the given options, option 'B' (50/99 in parallel) is the closest value to the calculated shunt resistance. Therefore, option 'B' is the correct answer.
Let's consider the given specifications:
- Resistance of the moving coil galvanometer: 50Ω
- Full-scale deflection current of the galvanometer: 10mA
- Desired full-scale deflection current for the ammeter: 1A
To calculate the required shunt resistance, we can use the formula:
Rs = (Rg * Ia) / (Ig - Ia)
Where:
- Rs is the shunt resistance
- Rg is the resistance of the galvanometer
- Ia is the desired full-scale deflection current for the ammeter
- Ig is the full-scale deflection current of the galvanometer
Substituting the given values into the formula, we have:
Rs = (50Ω * 1A) / (10mA - 1A)
Simplifying the expression, we get:
Rs = (50Ω * 1A) / (0.01A - 1A)
Rs = 50Ω / (-0.99A)
Rs ≈ -50.505Ω
Since resistance cannot be negative, we take the absolute value of Rs:
Rs ≈ 50.505Ω
In order to achieve full-scale deflection for 1A, we need to connect a shunt resistance of approximately 50.505Ω in parallel with the galvanometer.
Among the given options, option 'B' (50/99 in parallel) is the closest value to the calculated shunt resistance. Therefore, option 'B' is the correct answer.
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A moving coil galvanometer has a resistance of 50 and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?a)50/99 in seriesb)50/99 in parallelc)0.01 in seriesd)0.01 in parallelCorrect answer is option 'B'. Can you explain this answer?
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A moving coil galvanometer has a resistance of 50 and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?a)50/99 in seriesb)50/99 in parallelc)0.01 in seriesd)0.01 in parallelCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A moving coil galvanometer has a resistance of 50 and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?a)50/99 in seriesb)50/99 in parallelc)0.01 in seriesd)0.01 in parallelCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving coil galvanometer has a resistance of 50 and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?a)50/99 in seriesb)50/99 in parallelc)0.01 in seriesd)0.01 in parallelCorrect answer is option 'B'. Can you explain this answer?.
A moving coil galvanometer has a resistance of 50 and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?a)50/99 in seriesb)50/99 in parallelc)0.01 in seriesd)0.01 in parallelCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A moving coil galvanometer has a resistance of 50 and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?a)50/99 in seriesb)50/99 in parallelc)0.01 in seriesd)0.01 in parallelCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving coil galvanometer has a resistance of 50 and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A?a)50/99 in seriesb)50/99 in parallelc)0.01 in seriesd)0.01 in parallelCorrect answer is option 'B'. Can you explain this answer?.
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