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3× 2y=12 and ×y=6 find the value of 27׳ 8y³?
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3× 2y=12 and ×y=6 find the value of 27׳ 8y³?
**Given equations:**

1. 3× 2y=12
2. ×y=6

**Finding the value of 27׳ 8y³:**

To find the value of 27׳ 8y³, we need to substitute the value of x and y into the expression and then simplify it.

Let's solve the given equations step by step to find the values of x and y.

**Solving equation 1:**

3× 2y = 12

Rewriting the equation in a more simplified form:

6y = 12

Dividing both sides of the equation by 6:

y = 2

**Solving equation 2:**

×y = 6

Substituting the value of y from equation 1:

x × 2 = 6

Dividing both sides of the equation by 2:

x = 3

Now, we have found the values of x and y. Let's substitute these values into the expression 27׳ 8y³.

**Substituting x = 3 and y = 2 into the expression:**

27׳ 8y³

Replacing x with 3 and y with 2:

27(3)³ 8(2)³

**Simplifying the expression:**

27(3)³ = 27(27) = 729

8(2)³ = 8(8) = 64

Substituting these values back into the expression:

729 - 64

Now, subtracting 64 from 729:

729 - 64 = 665

Therefore, the value of 27׳ 8y³ is 665.

In summary, the given equations were solved step by step to find the values of x and y. Then, these values were substituted into the given expression, and after simplifying, the final result of 665 was obtained.
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