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In ΔABC, E and D are points on sides AB and AC respectively such that ∠ABC = ∠ADE. If AE = 3 cm, AD = 2 cm and EB = 2 cm, then length of DC is    (SSC CGL 1st Sit. 2014)
  • a)
    4 cm
  • b)
    4.5 cm
  • c)
    5.0 cm
  • d)
    5.5 cm
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In ΔABC, E and D are points on sides AB and AC respectively such...

In ΔADE and ΔABC
∠A = ∠D
∠B = ∠D
Then third angle ∠C = ∠E
(By AAA)
ΔADE ~ ΔABC

15 = 4 + 2 DC
11 = 2 DC
DC = 5.5 cm
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In ΔABC, E and D are points on sides AB and AC respectively such that ∠ABC = ∠ADE. If AE = 3 cm, AD = 2 cm and EB = 2 cm, then length of DC is (SSC CGL 1st Sit. 2014)a)4 cmb)4.5 cmc)5.0 cmd)5.5 cmCorrect answer is option 'D'. Can you explain this answer?
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