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One insulated wall of a cold chamber is 8 m long by 2.5 high and consists of an outer steel plate 18 mm thick , an outer steel plate 18 mm thick , an inner wood wall 22.5 mm thick , the steel and wood are 90 mm Apart to form a cavity which is filled with Cork . If the temperature drop across the extreme faces of composite wall is 15degree C , calcukate (i) the heat Transfer per hour through the wall (ii) the temperature drop through the thickness of the cork. Take the coefficent of thermal conductivity for steel , cork and work as 45, 0.045 and 0.18 W/m K respectively . solve using heat transfer method and put final answer in Kj and Centigrade?
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One insulated wall of a cold chamber is 8 m long by 2.5 high and consi...
**Given Data:**
- Length of the insulated wall (L) = 8 m
- Height of the insulated wall (H) = 2.5 m
- Thickness of the steel plates (d1) = 18 mm = 0.018 m
- Thickness of the wood wall (d2) = 22.5 mm = 0.0225 m
- Distance between steel and wood walls (d3) = 90 mm = 0.09 m
- Temperature drop across the extreme faces of the wall (ΔT) = 15 °C
- Thermal conductivity of steel (k1) = 45 W/mK
- Thermal conductivity of cork (k2) = 0.045 W/mK
- Thermal conductivity of wood (k3) = 0.18 W/mK

**Calculations:**

**1. Heat Transfer per Hour through the Wall:**
To calculate the heat transfer per hour through the wall, we need to find the overall thermal resistance (R) of the composite wall using the formula:

R = (d1/k1) + (d3/k2) + (d2/k3)

R = (0.018/45) + (0.09/0.045) + (0.0225/0.18)

R = 0.0004 + 2 + 0.125

R = 2.1254 °C/W

The heat transfer per hour (Q) through the wall can be calculated using the formula:

Q = (ΔT / R) * A

Where A is the area of the wall.

A = L * H = 8 * 2.5 = 20 m²

Q = (15 / 2.1254) * 20

Q ≈ 141.18 W

Therefore, the heat transfer per hour through the wall is approximately 141.18 W or 0.14118 kW.

**2. Temperature Drop through the Thickness of the Cork:**
To calculate the temperature drop through the thickness of the cork, we can use the formula:

ΔT_cork = (Q * d3) / (k2 * A)

ΔT_cork = (141.18 * 0.09) / (0.045 * 20)

ΔT_cork ≈ 7.882 °C

Therefore, the temperature drop through the thickness of the cork is approximately 7.882 °C.

**Final Answer:**
(i) The heat transfer per hour through the wall is approximately 141.18 W or 0.14118 kW.
(ii) The temperature drop through the thickness of the cork is approximately 7.882 °C.
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One insulated wall of a cold chamber is 8 m long by 2.5 high and consists of an outer steel plate 18 mm thick , an outer steel plate 18 mm thick , an inner wood wall 22.5 mm thick , the steel and wood are 90 mm Apart to form a cavity which is filled with Cork . If the temperature drop across the extreme faces of composite wall is 15degree C , calcukate (i) the heat Transfer per hour through the wall (ii) the temperature drop through the thickness of the cork. Take the coefficent of thermal conductivity for steel , cork and work as 45, 0.045 and 0.18 W/m K respectively . solve using heat transfer method and put final answer in Kj and Centigrade?
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One insulated wall of a cold chamber is 8 m long by 2.5 high and consists of an outer steel plate 18 mm thick , an outer steel plate 18 mm thick , an inner wood wall 22.5 mm thick , the steel and wood are 90 mm Apart to form a cavity which is filled with Cork . If the temperature drop across the extreme faces of composite wall is 15degree C , calcukate (i) the heat Transfer per hour through the wall (ii) the temperature drop through the thickness of the cork. Take the coefficent of thermal conductivity for steel , cork and work as 45, 0.045 and 0.18 W/m K respectively . solve using heat transfer method and put final answer in Kj and Centigrade? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One insulated wall of a cold chamber is 8 m long by 2.5 high and consists of an outer steel plate 18 mm thick , an outer steel plate 18 mm thick , an inner wood wall 22.5 mm thick , the steel and wood are 90 mm Apart to form a cavity which is filled with Cork . If the temperature drop across the extreme faces of composite wall is 15degree C , calcukate (i) the heat Transfer per hour through the wall (ii) the temperature drop through the thickness of the cork. Take the coefficent of thermal conductivity for steel , cork and work as 45, 0.045 and 0.18 W/m K respectively . solve using heat transfer method and put final answer in Kj and Centigrade? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One insulated wall of a cold chamber is 8 m long by 2.5 high and consists of an outer steel plate 18 mm thick , an outer steel plate 18 mm thick , an inner wood wall 22.5 mm thick , the steel and wood are 90 mm Apart to form a cavity which is filled with Cork . If the temperature drop across the extreme faces of composite wall is 15degree C , calcukate (i) the heat Transfer per hour through the wall (ii) the temperature drop through the thickness of the cork. Take the coefficent of thermal conductivity for steel , cork and work as 45, 0.045 and 0.18 W/m K respectively . solve using heat transfer method and put final answer in Kj and Centigrade?.
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