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If tan θ – cot θ = a and cos θ – sin θ = b, then the value of (a2 + 4) (b2 – 1)2 is: (SSC CGL 2nd Sit. 2012)
- a)4
- b)1
- c)2
- d)3
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
If tan θ – cot θ = a and cos θ – sin &th...
Put θ = 45°
a = tan 45° – cot 45°, b = sin 45° – cos 45°
a = 1 – 1 = 0
Put in equation
(a2 + 4) (b2 –1)2 = (0 + 4) (0 – 1)2 = 4
a = tan 45° – cot 45°, b = sin 45° – cos 45°
a = 1 – 1 = 0
Put in equation
(a2 + 4) (b2 –1)2 = (0 + 4) (0 – 1)2 = 4
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