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If 0 < θ < 90º , tanθ + sinθ = m and tan θ - sin θ = n, where m ≠ n , then value of m2 – n2 is (SSC Sub. Ins. 2016)a)2 (m2 + n2)b)4 √mnc)4 mnd)2(tan2θ + sin2θ)Correct answer is option 'B'. Can you explain this answer? for SSC CGL 2024 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about If 0 < θ < 90º , tanθ + sinθ = m and tan θ - sin θ = n, where m ≠ n , then value of m2 – n2 is (SSC Sub. Ins. 2016)a)2 (m2 + n2)b)4 √mnc)4 mnd)2(tan2θ + sin2θ)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for SSC CGL 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 0 < θ < 90º , tanθ + sinθ = m and tan θ - sin θ = n, where m ≠ n , then value of m2 – n2 is (SSC Sub. Ins. 2016)a)2 (m2 + n2)b)4 √mnc)4 mnd)2(tan2θ + sin2θ)Correct answer is option 'B'. Can you explain this answer?.

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