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Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)
- a)2 km, West
- b)5 km, East
- c)3 km, North
- d)3 km, South
Correct answer is option 'A'. Can you explain this answer?
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Johnson left for his office in his car. He drove 15km towards North an...
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Johnson left for his office in his car. He drove 15km towards North an...
And drove 20km. How far is he from his starting point and in which direction?
To solve this problem, we can use the Pythagorean theorem and the concept of vectors.
First, let's represent the distances covered in each direction as vectors. We can use the following notation:
- North: +15 km
- West: -10 km
- South: -5 km
- East: +20 km
Now, let's find the net displacement by adding these vectors together:
Net displacement = (15 km North) + (-10 km West) + (-5 km South) + (20 km East)
= 15N - 10W - 5S + 20E
Next, let's simplify this expression by combining the similar directions:
Net displacement = 15N - 5S - 10W + 20E
Now, let's rearrange the terms to group the similar directions:
Net displacement = (15N - 5S) + (-10W + 20E)
Finally, let's calculate the net displacement for each direction:
Net displacement in the North-South direction = 15N - 5S = 15 - 5 = 10 km North
Net displacement in the West-East direction = -10W + 20E = -10 + 20 = 10 km East
Therefore, Johnson is 10 km North and 10 km East from his starting point. The distance from his starting point can be calculated using the Pythagorean theorem:
Distance = √((Net displacement in the North-South direction)^2 + (Net displacement in the West-East direction)^2)
= √((10 km)^2 + (10 km)^2)
= √(100 km^2 + 100 km^2)
= √(200 km^2)
= 14.14 km (approximately)
So, Johnson is approximately 14.14 km away from his starting point in the direction of 10 km North and 10 km East.
To solve this problem, we can use the Pythagorean theorem and the concept of vectors.
First, let's represent the distances covered in each direction as vectors. We can use the following notation:
- North: +15 km
- West: -10 km
- South: -5 km
- East: +20 km
Now, let's find the net displacement by adding these vectors together:
Net displacement = (15 km North) + (-10 km West) + (-5 km South) + (20 km East)
= 15N - 10W - 5S + 20E
Next, let's simplify this expression by combining the similar directions:
Net displacement = 15N - 5S - 10W + 20E
Now, let's rearrange the terms to group the similar directions:
Net displacement = (15N - 5S) + (-10W + 20E)
Finally, let's calculate the net displacement for each direction:
Net displacement in the North-South direction = 15N - 5S = 15 - 5 = 10 km North
Net displacement in the West-East direction = -10W + 20E = -10 + 20 = 10 km East
Therefore, Johnson is 10 km North and 10 km East from his starting point. The distance from his starting point can be calculated using the Pythagorean theorem:
Distance = √((Net displacement in the North-South direction)^2 + (Net displacement in the West-East direction)^2)
= √((10 km)^2 + (10 km)^2)
= √(100 km^2 + 100 km^2)
= √(200 km^2)
= 14.14 km (approximately)
So, Johnson is approximately 14.14 km away from his starting point in the direction of 10 km North and 10 km East.
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Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer?
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Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer? for SSC CGL 2024 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC CGL 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer?.
Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer? for SSC CGL 2024 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC CGL 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer?.
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Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Johnson left for his office in his car. He drove 15km towards North and then 10km towards West. He then turned to the South and covered 5km. Further he turned to East & moved 8km. Finally he turned right and moved 10km. How far & in which direction is he from his starting point? (SSC CGL 2nd Sit. 2016)a)2 km, Westb)5 km, Eastc)3 km, Northd)3 km, SouthCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice SSC CGL tests.
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