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find out the contact force between 2kg and 3 kg block placed on the incline plane as shown in
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**Contact Force between 2kg and 3kg Block on Incline Plane**

To determine the contact force between the 2kg and 3kg blocks placed on an incline plane, we need to consider the forces acting on each block separately and then analyze their interaction.

**Forces on the 2kg Block:**

1. Weight (mg): The weight of the 2kg block acts vertically downward and can be calculated using the formula: Weight = mass * acceleration due to gravity. Therefore, the weight of the 2kg block is 2kg * 9.8m/s^2 = 19.6N.

2. Normal Force (N2): The normal force is the force exerted by the incline plane on the 2kg block perpendicular to the surface. Since the block is on the incline, the normal force will be less than the weight but still perpendicular to the incline.

3. Friction Force (f2): The friction force acts in the opposite direction to the motion or tendency of motion. In this case, the friction force is acting to prevent the 2kg block from sliding down the incline. The friction force depends on the coefficient of friction (μ) and the normal force (N2).

**Forces on the 3kg Block:**

1. Weight (mg): The weight of the 3kg block acts vertically downward and can be calculated using the formula: Weight = mass * acceleration due to gravity. Therefore, the weight of the 3kg block is 3kg * 9.8m/s^2 = 29.4N.

2. Normal Force (N3): The normal force is the force exerted by the incline plane on the 3kg block perpendicular to the surface. Since the block is on the incline, the normal force will be less than the weight but still perpendicular to the incline.

3. Friction Force (f3): The friction force acts in the opposite direction to the motion or tendency of motion. In this case, the friction force is acting to prevent the 3kg block from sliding down the incline. The friction force depends on the coefficient of friction (μ) and the normal force (N3).

**Interaction between the Blocks:**

When the 2kg and 3kg blocks are placed on the incline plane, they will exert a contact force on each other. This contact force can be determined by analyzing the forces acting on the blocks individually.

The contact force between the blocks can be determined using Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Therefore, the contact force exerted by the 2kg block on the 3kg block will be equal in magnitude and opposite in direction to the contact force exerted by the 3kg block on the 2kg block.

By analyzing the forces on each block separately and applying Newton's third law, we can determine the contact force between the 2kg and 3kg blocks on the incline plane.
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find out the contact force between 2kg and 3 kg block placed on the incline plane as shown in Related: NLM - Constrained Motion; Chapter Notes; Class 11; Physics (IIT-JEE and AIPMT)?
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