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How to find angle between the pair of lines r = 3i+2j-4k + α(i+2j+2k) and r = 5i-2k + β(3i+2j+6k) ?
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How to find angle between the pair of lines r = 3i+2j-4k + α(i+2j+2k) ...
If you can Solve.then equating real and imaginary parts of your answer is automatically on
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How to find angle between the pair of lines r = 3i+2j-4k + α(i+2j+2k) ...
Finding the Angle between Two Lines

To find the angle between two lines, we need to determine the direction vectors of the lines and then apply the formula for finding the angle between two vectors. Let's break down the process step by step:

Step 1: Determine the Direction Vectors of the Lines
To find the direction vectors of the lines, we look at the coefficients of the variables i, j, and k in the given equations. The direction vector of a line is the vector that describes the direction in which the line is moving.

Given:
Line α: r = 3i + 2j - 4k
Line β: r = 5i - 2k

The direction vector of Line α is <3, 2,="" -4="">.
The direction vector of Line β is <5, 0,="" -2="">.

Step 2: Apply the Formula for Finding the Angle between Two Vectors
The formula to find the angle θ between two vectors A and B is:

cosθ = (A • B) / (|A| * |B|)

where • represents the dot product and |A| and |B| represent the magnitudes of vectors A and B, respectively.

Step 3: Calculate the Dot Product and Magnitudes
Let's calculate the dot product and magnitudes using the given direction vectors:

Dot product of Line α and Line β:
A • B = (3 * 5) + (2 * 0) + (-4 * -2) = 15 + 0 + 8 = 23

Magnitude of Line α:
|A| = sqrt(3^2 + 2^2 + (-4)^2) = sqrt(9 + 4 + 16) = sqrt(29)

Magnitude of Line β:
|B| = sqrt(5^2 + 0^2 + (-2)^2) = sqrt(25 + 0 + 4) = sqrt(29)

Step 4: Calculate the Angle
Using the formula for finding the angle between two vectors, we can now calculate the angle θ:

cosθ = (A • B) / (|A| * |B|)
cosθ = 23 / (sqrt(29) * sqrt(29))
cosθ = 23 / 29
θ = arccos(23 / 29)

Using a calculator, we find that arccos(23 / 29) is approximately 0.733 radians or 42.05 degrees.

Step 5: Final Answer
The angle between Line α and Line β is approximately 0.733 radians or 42.05 degrees.
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How to find angle between the pair of lines r = 3i+2j-4k + α(i+2j+2k) and r = 5i-2k + β(3i+2j+6k) ?
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How to find angle between the pair of lines r = 3i+2j-4k + α(i+2j+2k) and r = 5i-2k + β(3i+2j+6k) ? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about How to find angle between the pair of lines r = 3i+2j-4k + α(i+2j+2k) and r = 5i-2k + β(3i+2j+6k) ? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How to find angle between the pair of lines r = 3i+2j-4k + α(i+2j+2k) and r = 5i-2k + β(3i+2j+6k) ?.
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