To solve this problem, let's break down Radha's movements and plot them on a grid.

1. Radha moves towards South-east a distance of 7 Km.
- This means she moves 7 Km diagonally towards the bottom-right direction.
- We can mark this point as (-7, -7) on the grid.

2. Radha then moves towards West and travels a distance of 14 m.
- This means she moves 14 m horizontally towards the left direction.
- We can mark this point as (-21, -7) on the grid.

3. From here, Radha moves towards North-west a distance of 7 m.
- This means she moves 7 m diagonally towards the top-left direction.
- We can mark this point as (-14, 0) on the grid.

4. Finally, Radha moves a distance of 4 m towards East and stood at that point.
- This means she moves 4 m horizontally towards the right direction.
- We can mark this point as (-10, 0) on the grid.

Now, we need to find the distance between the starting point and where Radha stood.

The starting point is (0, 0) on the grid.

Using the distance formula, which is √((x2 - x1)^2 + (y2 - y1)^2), we can calculate the distance between the starting point and Radha's final position.

Distance = √((-10 - 0)^2 + (0 - 0)^2)
= √((-10)^2 + 0^2)
= √(100 + 0)
= √100
= 10

Therefore, the distance between the starting point and where Radha stood is 10 m.

Hence, the correct answer is option C) 10 m.

Given information:
- Radha moves towards South-east a distance of 7 km.
- She then moves towards West and travels a distance of 14 m.
- From here, she moves towards North-west a distance of 7 m.
- Finally, she moves a distance of 4 m towards East and stands at that point.

To find: How far is the starting point from where she stood?

Let's break down Radha's movements and analyze them step by step:

1. South-east movement:
- Radha moves 7 km towards South-east. This movement can be represented as a diagonal movement combining South and East directions.
- In a right-angled triangle, the sides representing South and East are perpendicular to each other.
- The distance covered in the South direction is equal to the distance covered in the East direction.
- So, the South and East distances covered will be 7/√2 km each.

2. West movement:
- Radha moves 14 m towards the West direction.
- This movement is in a straight line and opposite to the East direction.

3. North-west movement:
- Radha moves 7 m towards the North-west direction.
- This movement can be represented as a diagonal movement combining North and West directions.
- In a right-angled triangle, the sides representing North and West are perpendicular to each other.
- The distance covered in the North direction is equal to the distance covered in the West direction.
- So, the North and West distances covered will be 7/√2 m each.

4. East movement:
- Radha moves 4 m towards the East direction.
- This movement is in a straight line and opposite to the West direction.

To calculate the total displacement from the starting point, we need to consider the net distances covered in the South and North directions, and the net distances covered in the East and West directions.

- Net South distance = 7/√2 km
- Net North distance = 7/√2 m
- Net East distance = 4 m
- Net West distance = 14 m

To find the total displacement, we need to find the difference between the net distances covered in the South and North directions, and the net distances covered in the East and West directions.

- Total South-North displacement = Net South distance - Net North distance = (7/√2 km) - (7/√2 m) = 0 km
- Total East-West displacement = Net East distance - Net West distance = 4 m - 14 m = -10 m

As the total South-North displacement is 0 km and the total East-West displacement is -10 m, it means that Radha has moved 10 m towards the West direction.

Therefore, the distance from the starting point to where Radha stood is 10 m.

Hence, the correct answer is option (c) 10 m.