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Find the least number when divided by 12,13,14 leaves a remainder of 2 in each case Solution: LCM of 12,13,14 =2 x 6 x 7 x 13 =1092 1092 is exactly divisible by 12,13,14. The number that leaves a remainder of 2 when divided by 12,13,14 =1092 2?
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Find the least number when divided by 12,13,14 leaves a remainder of 2...
To find the least number that leaves a remainder of 2 when divided by 12, 13, and 14, we need to find the least common multiple (LCM) of these three numbers.

1. Find the LCM of 12, 13, and 14:
- Prime factorize each number:
- 12 = 2 x 2 x 3
- 13 = 13
- 14 = 2 x 7
- Take the highest power of each prime factor:
- LCM = 2 x 2 x 3 x 7 x 13 = 2184

2. Now, find the number that leaves a remainder of 2 when divided by 12, 13, and 14.
- Divide the LCM by each number and add 2:
- 2184 ÷ 12 = 182 remainder 0
- 2184 ÷ 13 = 168 remainder 0
- 2184 ÷ 14 = 156 remainder 0
- So, the number that leaves a remainder of 2 when divided by 12, 13, and 14 is 2184 + 2 = 2186.

Therefore, the least number that leaves a remainder of 2 when divided by 12, 13, and 14 is 2186.
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Find the least number when divided by 12,13,14 leaves a remainder of 2 in each case Solution: LCM of 12,13,14 =2 x 6 x 7 x 13 =1092 1092 is exactly divisible by 12,13,14. The number that leaves a remainder of 2 when divided by 12,13,14 =1092 2?
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