Distance and Time Relations in Two Systems of Units

In two systems of units, denoted as System 1 and System 2, the relations for distance and time can be explained as follows:

1. Distance Relation:
In System 1, let the distance be denoted as d1, and in System 2, let the distance be denoted as d2. The relation between the two systems is given by:

d2 = m * d1

Here, 'm' is a constant that relates the distances in the two systems. This means that to convert a distance from System 1 to System 2, we need to multiply it by the constant 'm'.

2. Time Relation:
In System 1, let the time be denoted as t1, and in System 2, let the time be denoted as t2. The relation between the two systems is given by:

t2 = n * t1

Similarly, 'n' is a constant that relates the times in the two systems. To convert a time from System 1 to System 2, we need to multiply it by the constant 'n'.

Velocity and Acceleration Relations:
Now, let's relate the velocity and acceleration in the two systems using the given relations:

1. Velocity (v):
In System 1, let the velocity be denoted as v1, and in System 2, let the velocity be denoted as v2. The relation between the two systems is given by:

v2 = v1 / m

Here, we divide the velocity in System 1 by the constant 'm' to obtain the velocity in System 2.

2. Acceleration (a):
In System 1, let the acceleration be denoted as a1, and in System 2, let the acceleration be denoted as a2. The relation between the two systems is given by:

a2 = a1 / (m * n)

Here, we divide the acceleration in System 1 by the product of the constants 'm' and 'n' to obtain the acceleration in System 2.

Summary:
To summarize, in the two systems of units, the distances are related by multiplying by a constant 'm' and the times are related by multiplying by a constant 'n'. The velocity in System 2 is obtained by dividing the velocity in System 1 by 'm', and the acceleration in System 2 is obtained by dividing the acceleration in System 1 by the product of 'm' and 'n'.

N3/m3 L1=L2 AND n2/m T1= T2 answer to this question.