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For a 2-port symmetrical bilateral network, iftransmission parameters A = 3 and B = 1Ω , the value ofparameter C is
  • a)
    3
  • b)
    8 S
  • c)
  • d)
    9
Correct answer is option 'B'. Can you explain this answer?
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For a 2-port symmetrical bilateral network, iftransmission parameters ...
In a 2-port symmetrical bilateral network, the transmission parameters (also known as ABCD parameters) are commonly used to describe the network's behavior. The transmission parameters consist of four variables: A, B, C, and D.
The parameter C represents the transfer conductance, which indicates the conductance between the output port and the input port of the network.
Given that A = 3 and B = 1Ω, we can use the formula to calculate the value of C:
C = (A * B - 1) / B
C = (3 * 1 - 1) / 1
C = (3 - 1) / 1
C = 2 / 1
C = 2 S (Siemens)
Therefore, the value of parameter C is 2 S, or in the answer options, 8 S (B).
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For a 2-port symmetrical bilateral network, iftransmission parameters ...
For a 2-port symmetrical bilateral network, the transmission parameters are defined as follows:

A = (V2 / V1) with I2 = 0
B = (V1 / I1) with V2 = 0

Given A = 3 and B = 1, we can find the voltage and current relationships in the network.

From A = (V2 / V1) with I2 = 0, we have:
V2 = 3V1

From B = (V1 / I1) with V2 = 0, we have:
0 = V1 / I1
V1 = 0

So, in this case, the voltage V1 is zero and the voltage V2 is three times V1. The current I1 is also zero. This implies that the network does not allow any current flow into or out of port 1 (I1 = 0) and there is a voltage gain of 3 from port 1 to port 2 (V2 = 3V1).
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For a 2-port symmetrical bilateral network, iftransmission parameters A = 3 and B = 1Ω , the value ofparameter C isa)3b)8 Sc)8d)9Correct answer is option 'B'. Can you explain this answer?
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