Let the first multiple be x.Let the second multiple be x+11.Let the third multiple be x+22.According to the questionx+x+11+x+22=3633x+33 =363x=110So the first multiple is 110, second multiple is 121 and the third multiple is 132.

Question: The sum of three consecutive multiples of 11 is 363. Find these multiples.

Solution:

To find three consecutive multiples of 11 that sum up to 363, we can set up an equation and solve for the unknown multiples.

Let's assume the first multiple of 11 is x. Therefore, the second multiple would be x + 11, and the third multiple would be x + 22.

Equation:
x + (x + 11) + (x + 22) = 363

Simplifying the equation:
3x + 33 = 363

Now, let's solve for x.

Subtract 33 from both sides of the equation:
3x = 330

Divide both sides by 3:
x = 110

First Multiple:
The first multiple of 11 is x = 110.

Second Multiple:
The second multiple of 11 is x + 11 = 110 + 11 = 121.

Third Multiple:
The third multiple of 11 is x + 22 = 110 + 22 = 132.

Verification:
To verify our solution, let's check if the sum of these three multiples equals 363.

110 + 121 + 132 = 363

Therefore, the three consecutive multiples of 11 that sum up to 363 are 110, 121, and 132.

Summary:
- The first multiple of 11 is 110.
- The second multiple of 11 is 121.
- The third multiple of 11 is 132.

These three numbers satisfy the condition that their sum is 363.