If base of isosceles triangle is 6 cm and perimeter 16 cm . Find area ?

Question

Answer

Perimeter of triangle= a+b+c16= 6+6+c16=12+c16-12=c4=c area of triangle=s=a+b+c÷2=6+6+4÷2=16÷2=8area of triangle=√s(s-a)(s-b)(s-c)=√8(8-6)(8-6)(8-4)=√8×2×2×4=√2×2×2×2×2×2×2=√2^2×2^2×2^2×2=2×2×2√2=8√2 hence the area of triangle is 8√2

Answer

Base of triangle is 6 cm so other two sides of the triangle will be equal as per information given in the question and also it is isosceles triangle.so 6+a+a=16cm 2a=16 - 6 cm 2a = 10a= 5cms= a+b+c /2s=5+5+6/2s= 16/2s= 8cmarea= √s (s-a) (s-b) (s-c)=√8 (8-5) (8-5) (8-6)=√8×3 × 3×2=3√8×2=3√4×2×2=3√4×4=3×4=12 cm²so, area of isosceles triangle is 12cm².

Answer

Perimeter of triangle is a+b+c6+x+x=162x =16-6=10x=5

Answer

Thanks

Answer

12

Answer

Perimeter=16cm6+x+x=162x=10x=5a=5cm, b=5cm, c=6cms=a+b+c/2 =8cmarea of triangle=√s(s-a)(s-b)(s-c)=√8*3*3*2=12cm²

Answer

12cmcm

Answer

Given Information:

- Base of the isosceles triangle = 6 cm
- Perimeter of the triangle = 16 cm

To Find:

- Area of the isosceles triangle

Solution:

Step 1: Finding the Length of the Two Equal Sides

- An isosceles triangle has two equal sides.
- Let's assume the length of each equal side as 'x' cm.

- Perimeter of a triangle = Sum of all sides

- Given that the perimeter of the triangle is 16 cm, we can express this as:
6 cm + x cm + x cm = 16 cm

- Simplifying the equation, we get:
2x + 6 = 16

- Subtracting 6 from both sides, we obtain:
2x = 10

- Dividing both sides by 2, we find:
x = 5

- Therefore, each equal side of the triangle is 5 cm.

Step 2: Finding the Height of the Triangle

- The height of an isosceles triangle is the perpendicular distance from the base to the top vertex.
- To find the height, we can draw an altitude from the top vertex to the base, dividing the base into two equal segments.

- Since the triangle is isosceles, the altitude will also bisect the base.
- We can calculate the length of half the base as follows:
Half of the base = 6 cm / 2 = 3 cm

- Using the Pythagorean theorem, we can find the height of the triangle:
(Height)^2 = (Length of one equal side)^2 - (Half of the base)^2
= 5 cm^2 - 3 cm^2
= 25 cm^2 - 9 cm^2
= 16 cm^2

- Taking the square root of both sides, we get:
Height = √16 cm^2
= 4 cm

Step 3: Finding the Area of the Triangle

- The area of a triangle can be calculated using the formula:
Area = (1/2) * Base * Height

- Substituting the given values, we have:
Area = (1/2) * 6 cm * 4 cm
= 12 cm^2

Answer:

- The area of the isosceles triangle is 12 cm^2.

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