If base of isosceles triangle is 6 cm and perimeter 16 cm . Find area ?

Question

Answer

Perimeter of triangle= a+b+c16= 6+6+c16=12+c16-12=c4=c area of triangle=s=a+b+c÷2=6+6+4÷2=16÷2=8area of triangle=√s(s-a)(s-b)(s-c)=√8(8-6)(8-6)(8-4)=√8×2×2×4=√2×2×2×2×2×2×2=√2^2×2^2×2^2×2=2×2×2√2=8√2 hence the area of triangle is 8√2

Answer

Base of triangle is 6 cm so other two sides of the triangle will be equal as per information given in the question and also it is isosceles triangle.so 6+a+a=16cm 2a=16 - 6 cm 2a = 10a= 5cms= a+b+c /2s=5+5+6/2s= 16/2s= 8cmarea= √s (s-a) (s-b) (s-c)=√8 (8-5) (8-5) (8-6)=√8×3 × 3×2=3√8×2=3√4×2×2=3√4×4=3×4=12 cm²so, area of isosceles triangle is 12cm².

Answer

Perimeter of triangle is a+b+c6+x+x=162x =16-6=10x=5

Answer

Thanks

Answer

12

Answer

Perimeter=16cm6+x+x=162x=10x=5a=5cm, b=5cm, c=6cms=a+b+c/2 =8cmarea of triangle=√s(s-a)(s-b)(s-c)=√8*3*3*2=12cm²

Answer

12cmcm

Answer

Given Information:

- Base of the isosceles triangle = 6 cm
- Perimeter of the triangle = 16 cm

To Find:

- Area of the isosceles triangle

Solution:

Step 1: Finding the Length of the Two Equal Sides

- An isosceles triangle has two equal sides.
- Let's assume the length of each equal side as 'x' cm.

- Perimeter of a triangle = Sum of all sides

- Given that the perimeter of the triangle is 16 cm, we can express this as:
6 cm + x cm + x cm = 16 cm

- Simplifying the equation, we get:
2x + 6 = 16

- Subtracting 6 from both sides, we obtain:
2x = 10

- Dividing both sides by 2, we find:
x = 5

- Therefore, each equal side of the triangle is 5 cm.

Step 2: Finding the Height of the Triangle

- The height of an isosceles triangle is the perpendicular distance from the base to the top vertex.
- To find the height, we can draw an altitude from the top vertex to the base, dividing the base into two equal segments.

- Since the triangle is isosceles, the altitude will also bisect the base.
- We can calculate the length of half the base as follows:
Half of the base = 6 cm / 2 = 3 cm

- Using the Pythagorean theorem, we can find the height of the triangle:
(Height)^2 = (Length of one equal side)^2 - (Half of the base)^2
= 5 cm^2 - 3 cm^2
= 25 cm^2 - 9 cm^2
= 16 cm^2

- Taking the square root of both sides, we get:
Height = √16 cm^2
= 4 cm

Step 3: Finding the Area of the Triangle

- The area of a triangle can be calculated using the formula:
Area = (1/2) * Base * Height

- Substituting the given values, we have:
Area = (1/2) * 6 cm * 4 cm
= 12 cm^2

Answer:

- The area of the isosceles triangle is 12 cm^2.

Similar Class 9 Doubts

The area of the isosceles triangle is 5/4√11 cm square if the perimeter is 11 cm and the base is 5 cm. It is right.?? Explain it.?

The base of isosceles triangle is 24 cm and its area is 192 cm^2.find its perimeter?

If the base of an isosceles triangle is 12cm and it's perimeter is 35cm Find the area of triangle?

The perimeter of isosceles triangle is 42 cm . It's base is 3/2 times , each of equal sides Find area and height?

An isosceles triangle has perimeter 30 cm and each of the equal sides is 12cm. Find the area of the triangle.?

Top Courses for Class 9View all

Science Class 9

Social Studies (SST) Class 9

Mathematics (Maths) Class 9

English Class 9

English Grammar Advanced

Top Courses for Class 9

Top Courses for Class 9

Suggested Free Tests

Related Content

Class 9 Study Material

Class 9 Subjects

Competitive Examinations for Class 9

NCERT Books

NCERT Solutions

Reference Books for Class 9

Other Popular Exams

Company