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A body starts to fall freely under gravity. The distances covered by it in first, second and third second will be in the ratio
- a)1 : 3 : 5
- b)1 : 2 : 3
- c)1 : 4 : 9
- d)1 : 5 : 6
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A body starts to fall freely under gravity. The distances covered by i...
According to equation of motion, distance covered in nth sec.
Sn = u = a/2 (2n - 1)
Sn = a/2 (2n - 1)
∴ S1 : S2 : S3 = {2(1)−1} : {2(2)−1} : {2(3)−1}
= 1 : 3 : 5
Sn = u = a/2 (2n - 1)
Sn = a/2 (2n - 1)
∴ S1 : S2 : S3 = {2(1)−1} : {2(2)−1} : {2(3)−1}
= 1 : 3 : 5
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Community Answer
A body starts to fall freely under gravity. The distances covered by i...
Concept:
When a body falls freely under gravity, the distance covered by it in each second forms an arithmetic progression.
Explanation:
- First Second: In the first second, the distance covered is given by the formula d = 1/2 * g * t^2, where g is the acceleration due to gravity and t is the time taken (1 second in this case). Therefore, the distance covered in the first second is 1/2 * g.
- Second Second: In the second second, the distance covered is 3/2 times the distance covered in the first second. Therefore, the distance covered in the second second is 3/2 * 1/2 * g = 3/4 * g.
- Third Second: Similarly, in the third second, the distance covered is 5/2 times the distance covered in the first second. Therefore, the distance covered in the third second is 5/2 * 1/2 * g = 5/4 * g.
Therefore, the distances covered in the first, second, and third seconds are in the ratio 1 : 3 : 5. Hence, the correct answer is option 'A'.
When a body falls freely under gravity, the distance covered by it in each second forms an arithmetic progression.
Explanation:
- First Second: In the first second, the distance covered is given by the formula d = 1/2 * g * t^2, where g is the acceleration due to gravity and t is the time taken (1 second in this case). Therefore, the distance covered in the first second is 1/2 * g.
- Second Second: In the second second, the distance covered is 3/2 times the distance covered in the first second. Therefore, the distance covered in the second second is 3/2 * 1/2 * g = 3/4 * g.
- Third Second: Similarly, in the third second, the distance covered is 5/2 times the distance covered in the first second. Therefore, the distance covered in the third second is 5/2 * 1/2 * g = 5/4 * g.
Therefore, the distances covered in the first, second, and third seconds are in the ratio 1 : 3 : 5. Hence, the correct answer is option 'A'.
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A body starts to fall freely under gravity. The distances covered by it in first, second and third second will be in the ratioa)1 : 3 : 5b)1 : 2 : 3c)1 : 4 : 9d)1 : 5 : 6Correct answer is option 'A'. Can you explain this answer?
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