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What will be the output of the following code snippet?
#include <stdio.h>
#define VAL 5
int getInput() {
    return VAL;
}
void solve() {
    const int x = getInput();
    printf("%d", x);
}
int main() {
    solve();
    return 0;
}
  • a)
    5
  • b)
    Garbage Value
  • c)
    Compilation Error
  • d)
    0
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following code snippet?#include <std...

Explanation:

Constant x is initialized with the value returned by getInput() function:
- The solve() function initializes a constant integer x with the value returned by the getInput() function, which is defined as VAL in the code snippet.

Value of VAL is defined as 5:
- The macro VAL is defined as 5 using #define VAL 5.

Prints the value of constant x:
- The solve() function then prints the value of the constant x using printf() function.

Output:
- The output of the code snippet will be 5.

Therefore, the correct output is option 'A) 5'.
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Community Answer
What will be the output of the following code snippet?#include <std...
The code snippet provided defines a macro VAL with a value of 5. The function getInput() returns the value of the macro VAL, which is 5. In the solve() function, a constant integer x is declared and assigned the value returned by getInput(), which is 5. Finally, in the main() function, the solve() function is called, and it prints the value of x, which is 5, using printf().
Therefore, when the code is executed, the output will be "5".
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What will be the output of the following code snippet?#include <stdio.h>#define VAL 5int getInput() { return VAL;}void solve() { const int x = getInput(); printf("%d", x);}int main() { solve(); return 0;}a)5b)Garbage Valuec)Compilation Errord)0Correct answer is option 'A'. Can you explain this answer?
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