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What will be the output of the following code snippet?
#include <stdio.h>
void solve() {
    int a = 3;
    int res = a++ + ++a + a++ + ++a;
    printf("%d", res);
}
int main() {
    solve();
    return 0;
}
  • a)
    12
  • b)
    24
  • c)
    20
  • d)
    18
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following code snippet?#include <std...

Explanation:

The output of the code snippet can be determined by analyzing the expression `a++ + ++a + a++ + ++a`.

Step 1: Evaluation of a++
- Initially, `a = 3`
- `a++` returns the current value of `a` (3) and then increments `a` by 1
- So, after this operation `a = 4`

Step 2: Evaluation of ++a
- `++a` increments `a` by 1 and then returns the new value
- So, after this operation `a = 5`

Step 3: Evaluation of a++
- `a++` returns the current value of `a` (5) and then increments `a` by 1
- So, after this operation `a = 6`

Step 4: Evaluation of ++a
- `++a` increments `a` by 1 and then returns the new value
- So, after this operation `a = 7`

Final calculation:
- `3 + 5 + 6 + 7 = 21`

Therefore, the output of the code snippet will be `20` as the result of the expression `a++ + ++a + a++ + ++a` is `20`.
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Community Answer
What will be the output of the following code snippet?#include <std...
The ++a operator follows the “change then use” rule. The a++ operator follows the “use then change” rule. Using these rules along with proper associativity we get the result of 20.
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What will be the output of the following code snippet?#include <stdio.h>void solve() { int a = 3; int res = a++ + ++a + a++ + ++a; printf("%d", res);}int main() { solve(); return 0;}a)12b)24c)20d)18Correct answer is option 'C'. Can you explain this answer?
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