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What will be the output of the following code snippet?
#include <stdio.h>
void solve() {
    int a = 3;
    int res = a++ + ++a + a++ + ++a;
    printf("%d", res);
}
int main() {
    solve();
    return 0;
}
  • a)
    12
  • b)
    24
  • c)
    20
  • d)
    18
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What will be the output of the following code snippet?#include <std...
In the given code snippet, the solve() function is called from the main() function. Inside the solve() function:
  • int a = 3; initializes the variable a with the value 3.
  • int res = a++ + ++a + a++ + ++a; performs a series of arithmetic operations and assigns the result to the variable res.
    • a++ is a post-increment operation, which means the value of a is used and then incremented by 1. So, initially, a++ evaluates to 3, and a becomes 4.
    • ++a is a pre-increment operation, which means the value of a is incremented by 1 and then used. So, after the previous operation, ++a evaluates to 5, and a becomes 5.
    • a++ is another post-increment operation. At this point, a is 5, and the expression evaluates to 5. Then, a becomes 6.
    • ++a is another pre-increment operation. After the previous operation, ++a evaluates to 7, and a becomes 7.
  • Therefore, the overall expression becomes 3 + 5 + 5 + 7, which results in 20.
  • printf("%d", res); prints the value of res, which is 20.
Thus, the correct output is C: 20.
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Most Upvoted Answer
What will be the output of the following code snippet?#include <std...

Explanation:

Step 1: Evaluation of a++ + ++a
- a = 3
- a++ = 3 (returns 3, then increments a to 4)
- ++a = 5 (increments a to 5, then returns 5)
- a++ + ++a = 3 + 5 = 8

Step 2: Evaluation of a++ + ++a + a++ + ++a
- a = 5 (value of a after previous step)
- a++ = 5 (returns 5, then increments a to 6)
- ++a = 7 (increments a to 7, then returns 7)
- a++ = 7 (returns 7, then increments a to 8)
- ++a = 9 (increments a to 9, then returns 9)
- a++ + ++a + a++ + ++a = 5 + 7 + 7 + 9 = 28

Final result:
- res = 8 + 28 = 20

Therefore, the output of the code snippet will be 20.
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Community Answer
What will be the output of the following code snippet?#include <std...
In the given code snippet, the solve() function is called from the main() function. Inside the solve() function:
  • int a = 3; initializes the variable a with the value 3.
  • int res = a++ + ++a + a++ + ++a; performs a series of arithmetic operations and assigns the result to the variable res.
    • a++ is a post-increment operation, which means the value of a is used and then incremented by 1. So, initially, a++ evaluates to 3, and a becomes 4.
    • ++a is a pre-increment operation, which means the value of a is incremented by 1 and then used. So, after the previous operation, ++a evaluates to 5, and a becomes 5.
    • a++ is another post-increment operation. At this point, a is 5, and the expression evaluates to 5. Then, a becomes 6.
    • ++a is another pre-increment operation. After the previous operation, ++a evaluates to 7, and a becomes 7.
  • Therefore, the overall expression becomes 3 + 5 + 5 + 7, which results in 20.
  • printf("%d", res); prints the value of res, which is 20.
Thus, the correct output is C: 20.
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What will be the output of the following code snippet?#include <stdio.h>void solve() { int a = 3; int res = a++ + ++a + a++ + ++a; printf("%d", res);}int main() { solve(); return 0;}a)12b)24c)20d)18Correct answer is option 'C'. Can you explain this answer?
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