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Directions: Directions: Select a single answer choice.
Q. By weight, liquid A makes up 8 percent of solution R and 18 percent of solution S. If 3 grams of solution R are mixed with 7 grams of solution S, then liquid A accounts for what percent of the weight of the resulting
- a)10%
- b)13%
- c)15%
- d)19%
- e)26%
Correct answer is option 'C'. Can you explain this answer?
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Directions: Directions: Select a single answer choice.Q. By weight, l...
Solution:
To solve this problem, we need to determine the percentage of liquid A in the resulting mixture when 3 grams of solution R are mixed with 7 grams of solution S.
Let's start by finding the amount of liquid A in solution R and solution S separately.
In solution R, liquid A makes up 8 percent of the weight. Therefore, the amount of liquid A in solution R is 8 percent of 3 grams, which is (8/100) * 3 = 0.24 grams.
Similarly, in solution S, liquid A makes up 18 percent of the weight. Therefore, the amount of liquid A in solution S is 18 percent of 7 grams, which is (18/100) * 7 = 1.26 grams.
Next, we need to find the total amount of liquid A in the resulting mixture.
When we mix 3 grams of solution R with 7 grams of solution S, we have a total weight of 3 + 7 = 10 grams.
The total amount of liquid A in the resulting mixture is the sum of the amounts of liquid A in solution R and solution S, which is 0.24 grams + 1.26 grams = 1.5 grams.
Finally, we need to determine the percentage of liquid A in the resulting mixture.
The percentage of liquid A in the resulting mixture is the amount of liquid A divided by the total weight of the mixture, multiplied by 100.
So, the percentage of liquid A in the resulting mixture is (1.5/10) * 100 = 15%.
Therefore, the correct answer is option C, 15%.
To solve this problem, we need to determine the percentage of liquid A in the resulting mixture when 3 grams of solution R are mixed with 7 grams of solution S.
Let's start by finding the amount of liquid A in solution R and solution S separately.
In solution R, liquid A makes up 8 percent of the weight. Therefore, the amount of liquid A in solution R is 8 percent of 3 grams, which is (8/100) * 3 = 0.24 grams.
Similarly, in solution S, liquid A makes up 18 percent of the weight. Therefore, the amount of liquid A in solution S is 18 percent of 7 grams, which is (18/100) * 7 = 1.26 grams.
Next, we need to find the total amount of liquid A in the resulting mixture.
When we mix 3 grams of solution R with 7 grams of solution S, we have a total weight of 3 + 7 = 10 grams.
The total amount of liquid A in the resulting mixture is the sum of the amounts of liquid A in solution R and solution S, which is 0.24 grams + 1.26 grams = 1.5 grams.
Finally, we need to determine the percentage of liquid A in the resulting mixture.
The percentage of liquid A in the resulting mixture is the amount of liquid A divided by the total weight of the mixture, multiplied by 100.
So, the percentage of liquid A in the resulting mixture is (1.5/10) * 100 = 15%.
Therefore, the correct answer is option C, 15%.
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Directions: Directions: Select a single answer choice.Q. By weight, l...
Liquid A makes up 8 percent of the weight of solution R and 18 percent of the weight of solution S. Therefore, 3 grams of solution R contain (0.08)(3), or 0.24 gram of liquid A, and 7 grams of solution S contain (0.18)(7), or 1.26 grams of liquid A. When the two solutions are mixed, the resulting solution weighs 3 + 7, or 10 grams and contains 0.24 + 1.26, or 1.5 grams of liquid A. This means that liquid A makes up 1.5/10, or 15/100, or 15 percent of the weight of the resulting solution. The correct answer is Choice C.
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