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Two objects of masses 3.2×10 power6 and 3.2×10 power7 kg are kept 100 km apart find the force of attraction between them?
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Two objects of masses 3.2×10 power6 and 3.2×10 power7 kg are kept 100 ...
Given:
Mass of object 1 (m1) = 3.2 × 10^6 kg
Mass of object 2 (m2) = 3.2 × 10^7 kg
Distance between the objects (r) = 100 km = 100,000 m

To find:
The force of attraction between the objects.

Solution:

Newton's Law of Universal Gravitation:
The force of attraction between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The formula for gravitational force:
F = (G × m1 × m2) / r^2

where F is the force of attraction,
G is the gravitational constant (approximately 6.67 × 10^-11 Nm^2/kg^2),
m1 and m2 are the masses of the objects,
and r is the distance between the objects.

Substituting the given values:
m1 = 3.2 × 10^6 kg
m2 = 3.2 × 10^7 kg
r = 100,000 m

Calculating the force of attraction:
F = (6.67 × 10^-11 Nm^2/kg^2 × 3.2 × 10^6 kg × 3.2 × 10^7 kg) / (100,000 m)^2

Simplifying the expression:
F = (6.67 × 3.2 × 3.2 × 10^-11 × 10^6 × 10^7) / (100,000 × 100,000)

Applying the rules of exponents:
F = 6.67 × 3.2 × 3.2 × 10^-11+6+7 / 100,000^2

Calculating the values:
F = 6.67 × 3.2 × 3.2 × 10^2 / 100,000^2
F = 6.67 × 3.2 × 3.2 × 10^2 / 10^10

Applying the multiplication rule of exponents:
F = 6.67 × 3.2 × 3.2 × 10^2-10
F = 6.67 × 3.2 × 3.2 × 10^-8

Calculating the value:
F = 0.215 kg m^2/s^2

Answer:
The force of attraction between the two objects is 0.215 N.
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Two objects of masses 3.2×10 power6 and 3.2×10 power7 kg are kept 100 km apart find the force of attraction between them?
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