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If q be acute angle and tan (4θ – 50°) = cot (50° – θ), then the value of θ in degrees is:    (SSC CGL 1st Sit. 2015)
  • a)
    30
  • b)
    40
  • c)
    20
  • d)
    50
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If q be acute angle and tan (4θ – 50°) = cot (50° ...
tan(4θ - 50 ° ) = cot(50 °- θ)
⇒ tan (4θ – 50°) = tan (90 – (50° – θ))
⇒ 4θ – 50° = 90 – 50° + θ
⇒ 3θ = 90° ; θ = 30°.
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If q be acute angle and tan (4θ – 50°) = cot (50° – θ), then the value of θ in degrees is: (SSC CGL 1st Sit. 2015)a)30b)40c)20d)50Correct answer is option 'A'. Can you explain this answer?
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